06.09.2021 Views

Measure, Integration & Real Analysis, 2021a

Measure, Integration & Real Analysis, 2021a

Measure, Integration & Real Analysis, 2021a

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

Section 8A Inner Product Spaces 213<br />

8.2 Example inner product spaces<br />

• For n ∈ Z + , define an inner product on F n by<br />

〈(a 1 ,...,a n ), (b 1 ,...,b n )〉 = a 1 b 1 + ···+ a n b n<br />

for (a 1 ,...,a n ), (b 1 ,...,b n ) ∈ F n . When thinking of F n as an inner product<br />

space, we always mean this inner product unless the context indicates some other<br />

inner product.<br />

• Define an inner product on l 2 by<br />

〈(a 1 , a 2 ,...), (b 1 , b 2 ,...)〉 =<br />

∞<br />

∑ a k b k<br />

k=1<br />

for (a 1 , a 2 ,...), (b 1 , b 2 ,...) ∈ l 2 . Hölder’s inequality (7.9), as applied to counting<br />

measure on Z + and taking p = 2, implies that the infinite sum above<br />

converges absolutely and hence converges to an element of F. When thinking<br />

of l 2 as an inner product space, we always mean this inner product unless the<br />

context indicates some other inner product.<br />

• Define an inner product on C([0, 1]), which is the vector space of continuous<br />

functions from [0, 1] to F,by<br />

〈 f , g〉 =<br />

∫ 1<br />

0<br />

f g<br />

for f , g ∈ C([0, 1]). The definiteness requirement for an inner product is<br />

satisfied because if f : [0, 1] → F is a continuous function such that ∫ 1<br />

0 | f |2 = 0,<br />

then the function f is identically 0.<br />

• Suppose (X, S, μ) is a measure space. Define an inner product on L 2 (μ) by<br />

∫<br />

〈 f , g〉 =<br />

f g dμ<br />

for f , g ∈ L 2 (μ). Hölder’s inequality (7.9) with p = 2 implies that the integral<br />

above makes sense as an element of F. When thinking of L 2 (μ) as an inner<br />

product space, we always mean this inner product unless the context indicates<br />

some other inner product.<br />

Here we use L 2 (μ) rather than L 2 (μ) because the definiteness requirement fails<br />

on L 2 (μ) if there exist nonempty sets E ∈Ssuch that μ(E) =0 (consider<br />

〈χ E<br />

, χ E<br />

〉 to see the problem).<br />

The first two bullet points in this example are special cases of L 2 (μ), taking μ to<br />

be counting measure on either {1, . . . , n} or Z + .<br />

<strong>Measure</strong>, <strong>Integration</strong> & <strong>Real</strong> <strong>Analysis</strong>, by Sheldon Axler

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!