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Measure, Integration & Real Analysis, 2021a

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Section 5C Lebesgue <strong>Integration</strong> on R n 137<br />

5.36 product of open sets is open<br />

Suppose G 1 is an open subset of R m and G 2 is an open subset of R n . Then<br />

G 1 × G 2 is an open subset of R m+n .<br />

Proof Suppose (x, y) ∈ G 1 × G 2 . Then there exists an open cube D in R m centered<br />

at x and an open cube E in R n centered at y such that D ⊂ G 1 and E ⊂ G 2 .By<br />

reducing the size of either D or E, we can assume that the cubes D and E have the<br />

same side length. Thus D × E is an open cube in R m+n centered at (x, y) that is<br />

contained in G 1 × G 2 .<br />

We have shown that an arbitrary point in G 1 × G 2 is the center of an open cube<br />

contained in G 1 × G 2 . Hence G 1 × G 2 is an open subset of R m+n .<br />

When n = 1, the definition below of a Borel subset of R 1 agrees with our previous<br />

definition (2.29) of a Borel subset of R.<br />

5.37 Definition Borel set; B n<br />

• A Borel subset of R n is an element of the smallest σ-algebra on R n containing<br />

all open subsets of R n .<br />

• The σ-algebra of Borel subsets of R n is denoted by B n .<br />

Recall that a subset of R is open if and only if it is a countable disjoint union of<br />

open intervals. Part (a) in the result below provides a similar result in R n , although<br />

we must give up the disjoint aspect.<br />

5.38 open sets are countable unions of open cubes<br />

(a) A subset of R n is open in R n if and only if it is a countable union of open<br />

cubes in R n .<br />

(b) B n is the smallest σ-algebra on R n containing all the open cubes in R n .<br />

Proof We will prove (a), which clearly implies (b).<br />

The proof that a countable union of open cubes is open is left as an exercise for<br />

the reader (actually, arbitrary unions of open cubes are open).<br />

To prove the other direction, suppose G is an open subset of R n . For each x ∈ G,<br />

there is an open cube centered at x that is contained in G. Thus there is a smaller<br />

cube C x such that x ∈ C x ⊂ G and all coordinates of the center of C x are rational<br />

numbers and the side length of C x is a rational number. Now<br />

G = ⋃<br />

C x .<br />

x∈G<br />

However, there are only countably many distinct cubes whose center has all rational<br />

coordinates and whose side length is rational. Thus G is the countable union of open<br />

cubes.<br />

<strong>Measure</strong>, <strong>Integration</strong> & <strong>Real</strong> <strong>Analysis</strong>, by Sheldon Axler

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