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Measure, Integration & Real Analysis, 2021a

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Section 2A Outer <strong>Measure</strong> on R 21<br />

The previous result has the following important corollary. You may be familiar<br />

with Georg Cantor’s (1845–1918) original proof of the next result. The proof using<br />

outer measure that is presented here gives an interesting alternative to Cantor’s proof.<br />

2.17 nontrivial intervals are uncountable<br />

Every interval in R that contains at least two distinct elements is uncountable.<br />

Proof<br />

Suppose I is an interval that contains a, b ∈ R with a < b. Then<br />

|I| ≥|[a, b]| = b − a > 0,<br />

where the first inequality above holds because outer measure preserves order (see 2.5)<br />

and the equality above comes from 2.14. Because every countable subset of R has<br />

outer measure 0 (see 2.4), we can conclude that I is uncountable.<br />

Outer <strong>Measure</strong> is Not Additive<br />

We have had several results giving nice<br />

properties of outer measure. Now we<br />

come to an unpleasant property of outer<br />

measure.<br />

If outer measure were a perfect way to<br />

assign a size as an extension of the lengths<br />

of intervals, then the outer measure of the<br />

union of two disjoint sets would equal the<br />

Outer measure led to the proof<br />

above that R is uncountable. This<br />

application of outer measure to<br />

prove a result that seems<br />

unconnected with outer measure is<br />

an indication that outer measure has<br />

serious mathematical value.<br />

sum of the outer measures of the two sets. Sadly, the next result states that outer<br />

measure does not have this property.<br />

In the next section, we begin the process of getting around the next result, which<br />

will lead us to measure theory.<br />

2.18 nonadditivity of outer measure<br />

There exist disjoint subsets A and B of R such that<br />

|A ∪ B| ̸= |A| + |B|.<br />

Proof For a ∈ [−1, 1], let ã be the set of numbers in [−1, 1] that differ from a by a<br />

rational number. In other words,<br />

If a, b ∈ [−1, 1] and ã ∩ ˜b ̸= ∅, then<br />

ã = ˜b. (Proof: Suppose there exists d ∈<br />

ã ∩ ˜b. Then a − d and b − d are rational<br />

numbers; subtracting, we conclude that<br />

a − b is a rational number. The equation<br />

ã = {c ∈ [−1, 1] : a − c ∈ Q}.<br />

Think of ã as the equivalence class<br />

of a under the equivalence relation<br />

that declares a, c ∈ [−1, 1] to be<br />

equivalent if a − c ∈ Q.<br />

a − c =(a − b)+(b − c) now implies that if c ∈ [−1, 1], then a − c is a rational<br />

number if and only if b − c is a rational number. In other words, ã = ˜b.)<br />

<strong>Measure</strong>, <strong>Integration</strong> & <strong>Real</strong> <strong>Analysis</strong>, by Sheldon Axler

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