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Measure, Integration & Real Analysis, 2021a

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Self-adjoint Operators<br />

Section 10B Spectrum 299<br />

In this subsection, we look at a nice special class of bounded operators.<br />

10.44 Definition self-adjoint<br />

A bounded operator T on a Hilbert space is called self-adjoint if T ∗ = T.<br />

The definition of the adjoint implies that a bounded operator T on a Hilbert space<br />

V is self-adjoint if and only if 〈Tf, g〉 = 〈 f , Tg〉 for all f , g ∈ V. See Exercise 7 for<br />

an interesting result regarding this last condition.<br />

10.45 Example self-adjoint operators<br />

• Suppose b 1 , b 2 ,... is a bounded sequence in F. Define a bounded operator<br />

T : l 2 → l 2 by<br />

T(a 1 , a 2 ,...)=(a 1 b 1 , a 2 b 2 ,...).<br />

Then T ∗ : l 2 → l 2 is the operator defined by<br />

T ∗ (a 1 , a 2 ,...)=(a 1 b 1 , a 2 b 2 ,...).<br />

Hence T is self-adjoint if and only if b k ∈ R for all k ∈ Z + .<br />

• More generally, suppose (X, S, μ) is a σ-finite measure space and h ∈L ∞ (μ).<br />

Define a bounded operator M h ∈B ( L 2 (μ) ) by M h f = fh. Then M h ∗ = M h<br />

.<br />

Thus M h is self-adjoint if and only if μ({x ∈ X : h(x) /∈ R}) =0.<br />

• Suppose n ∈ Z + , K is an n-by-n matrix, and I K : F n → F n is the operator of<br />

matrix multiplication by K (thinking of elements of F n as column vectors). Then<br />

(I K ) ∗ is the operator of multiplication by the conjugate transpose of K, as shown<br />

in Example 10.10. Thus I K is a self-adjoint operator if and only if the matrix K<br />

equals its conjugate transpose.<br />

• More generally, suppose (X, S, μ) is a σ-finite measure space, K ∈L 2 (μ × μ),<br />

and I K is the integral operator on L 2 (μ) defined in Example 10.5. Define<br />

K ∗ : X × X → F by K ∗ (y, x) =K(x, y). Then (I K ) ∗ is the integral operator<br />

induced by K ∗ , as shown in Example 10.5. Thus if K ∗ = K, or in other words if<br />

K(x, y) =K(y, x) for all (x, y) ∈ X × X, then I K is self-adjoint.<br />

• Suppose U is a closed subspace of a Hilbert space V. Recall that P U denotes the<br />

orthogonal projection of V onto U (see Section 8B). We have<br />

〈P U f , g〉 = 〈P U f , P U g +(I − P U )g〉<br />

= 〈P U f , P U g〉<br />

= 〈 f − (I − P U ) f , P U g〉<br />

= 〈 f , P U g〉,<br />

where the second and fourth equalities above hold because of 8.37(a). The<br />

equation above shows that P U is a self-adjoint operator.<br />

<strong>Measure</strong>, <strong>Integration</strong> & <strong>Real</strong> <strong>Analysis</strong>, by Sheldon Axler

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