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Measure, Integration & Real Analysis, 2021a

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Section 10B Spectrum 311<br />

22 Suppose T is a self-adjoint operator on a complex Hilbert space. Prove that<br />

(T + iI)(T − iI) −1<br />

is a unitary operator.<br />

[The function z ↦→ (z + i)(z − i) −1 maps R to {z ∈ C : |z| = 1}\{1}.<br />

Thus this exercise provides another useful illustration of the analogies showing<br />

(a) unitary ⇐⇒ {z ∈ C : |z| = 1};(b) self-adjoint ⇐⇒ R.]<br />

For T a bounded operator on a Banach space, define e T by<br />

e T =<br />

∞<br />

T<br />

∑<br />

k<br />

k! .<br />

k=0<br />

23 (a) Prove that if T is a bounded operator on a Banach space V, then the infinite<br />

sum above converges in B(V) and ‖e T ‖≤e ‖T‖ .<br />

(b) Prove that if S, T are bounded operators on a Banach space V such that<br />

ST = TS, then e S e T = e S+T .<br />

(c) Prove that if T is a self-adjoint operator on a complex Hilbert space, then<br />

e iT is unitary.<br />

A bounded operator T on a Hilbert space is called a partial isometry if<br />

‖Tf‖ = ‖ f ‖ for all f ∈ (null T) ⊥ .<br />

24 Suppose (X, S, μ) is a σ-finite measure space and h ∈ L ∞ (μ). As usual, let<br />

M h ∈B ( L 2 (μ) ) denote the multiplication operator defined by M h f = fh.<br />

Prove that M h is a partial isometry if and only if there exists a set E ∈Ssuch<br />

that h = χ E<br />

.<br />

25 Suppose T is an isometry on a Hilbert space. Prove that T ∗ is a partial isometry.<br />

26 Suppose T is a bounded operator on a Hilbert space V. Prove that T is a partial<br />

isometry if and only if T ∗ T = P U for some closed subspace U of V.<br />

<strong>Measure</strong>, <strong>Integration</strong> & <strong>Real</strong> <strong>Analysis</strong>, by Sheldon Axler

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