06.09.2021 Views

Measure, Integration & Real Analysis, 2021a

Measure, Integration & Real Analysis, 2021a

Measure, Integration & Real Analysis, 2021a

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

62 Chapter 2 <strong>Measure</strong>s<br />

2E<br />

Convergence of Measurable Functions<br />

Recall that a measurable space is a pair (X, S), where X is a set and S is a σ-algebra<br />

on X. We defined a function f : X → R to be S-measurable if f −1 (B) ∈Sfor<br />

every Borel set B ⊂ R. In Section 2B we proved some results about S-measurable<br />

functions; this was before we had introduced the notion of a measure.<br />

In this section, we return to study measurable functions, but now with an emphasis<br />

on results that depend upon measures. The highlights of this section are the proofs of<br />

Egorov’s Theorem and Luzin’s Theorem.<br />

Pointwise and Uniform Convergence<br />

We begin this section with some definitions that you probably saw in an earlier course.<br />

2.82 Definition pointwise convergence; uniform convergence<br />

Suppose X is a set, f 1 , f 2 ,... is a sequence of functions from X to R, and f is a<br />

function from X to R.<br />

• The sequence f 1 , f 2 ,... converges pointwise on X to f if<br />

for each x ∈ X.<br />

lim f k(x) = f (x)<br />

k→∞<br />

In other words, f 1 , f 2 ,... converges pointwise on X to f if for each x ∈ X<br />

and every ε > 0, there exists n ∈ Z + such that | f k (x) − f (x)| < ε for all<br />

integers k ≥ n.<br />

• The sequence f 1 , f 2 ,... converges uniformly on X to f if for every ε > 0,<br />

there exists n ∈ Z + such that | f k (x) − f (x)| < ε for all integers k ≥ n and<br />

all x ∈ X.<br />

2.83 Example a sequence converging pointwise but not uniformly<br />

Suppose f k : [−1, 1] → R is the<br />

function whose graph is shown here<br />

and f : [−1, 1] → R is the function<br />

defined by<br />

{<br />

1 if x ̸= 0,<br />

f (x) =<br />

2 if x = 0.<br />

Then f 1 , f 2 ,...converges pointwise<br />

on [−1, 1] to f but f 1 , f 2 ,... does<br />

not converge uniformly on [−1, 1] to<br />

f , as you should verify.<br />

The graph of f k .<br />

<strong>Measure</strong>, <strong>Integration</strong> & <strong>Real</strong> <strong>Analysis</strong>, by Sheldon Axler

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!