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Measure, Integration & Real Analysis, 2021a

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Section 6E Consequences of Baire’s Theorem 191<br />

5 Suppose<br />

X = {0}∪<br />

and d(x, y) =|x − y| for x, y ∈ X.<br />

∞⋃ { 1k<br />

}<br />

(a) Show that (X, d) is a complete metric space.<br />

(b) Each set of the form {x} for x ∈ X is a closed subset of R that has an<br />

empty interior as a subset of R. Clearly X is a countable union of such sets.<br />

Explain why this does not violate the statement of Baire’s Theorem that<br />

a complete metric space is not the countable union of closed subsets with<br />

empty interior.<br />

6 Give an example of a metric space that is the countable union of closed subsets<br />

with empty interior.<br />

[This exercise shows that the completeness hypothesis in Baire’s Theorem cannot<br />

be dropped.]<br />

7 (a) Define f : R → R as follows:<br />

⎧<br />

⎪⎨ 0 if a is irrational,<br />

f (a) = 1<br />

⎪⎩<br />

n<br />

if a is rational and n is the smallest positive integer<br />

such that a = m n<br />

for some integer m.<br />

At which numbers in R is f continuous?<br />

(b) Show that there does not exist a countable collection of open subsets of R<br />

whose intersection equals Q.<br />

(c) Show that there does not exist a function f : R → R such that f is continuous<br />

at each element of Q and discontinuous at each element of R \ Q.<br />

8 Suppose (X, d) is a complete metric space and G 1 , G 2 ,... is a sequence of<br />

dense open subsets of X. Prove that ⋂ ∞<br />

k=1<br />

G k is a dense subset of X.<br />

9 Prove that there does not exist an infinite-dimensional Banach space with a<br />

countable basis.<br />

[This exercise implies, for example, that there is not a norm that makes the<br />

vector space of polynomials with coefficients in F into a Banach space.]<br />

10 Give an example of a Banach space V, a normed vector space W, a bounded<br />

linear map T of V onto W, and an open subset G of V such that T(G) is not an<br />

open subset of W.<br />

[This exercise shows that the hypothesis in the Open Mapping Theorem that<br />

W is a Banach space cannot be relaxed to the hypothesis that W is a normed<br />

vector space.]<br />

11 Show that there exists a normed vector space V, a Banach space W, a bounded<br />

linear map T of V onto W, and an open subset G of V such that T(G) is not an<br />

open subset of W.<br />

[This exercise shows that the hypothesis in the Open Mapping Theorem that V<br />

is a Banach space cannot be relaxed to the hypothesis that V is a normed vector<br />

space.]<br />

k=1<br />

<strong>Measure</strong>, <strong>Integration</strong> & <strong>Real</strong> <strong>Analysis</strong>, by Sheldon Axler

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