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Measure, Integration & Real Analysis, 2021a

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Section 3A <strong>Integration</strong> with Respect to a <strong>Measure</strong> 83<br />

Now we prove that integration with respect to a measure has the additive property<br />

required for a good theory of integration.<br />

3.21 additivity of integration<br />

Suppose (X, S, μ) is a measure space and f , g : X → R are S-measurable<br />

functions such that ∫ | f | dμ < ∞ and ∫ |g| dμ < ∞. Then<br />

∫<br />

∫<br />

( f + g) dμ =<br />

∫<br />

f dμ +<br />

g dμ.<br />

Proof Clearly<br />

( f + g) + − ( f + g) − = f + g<br />

= f + − f − + g + − g − .<br />

Thus<br />

( f + g) + + f − + g − =(f + g) − + f + + g + .<br />

Both sides of the equation above are sums of nonnegative functions. Thus integrating<br />

both sides with respect to μ and using 3.16 gives<br />

∫<br />

∫ ∫ ∫<br />

∫ ∫<br />

( f + g) + dμ + f − dμ + g − dμ = ( f + g) − dμ + f + dμ + g + dμ.<br />

Rearranging the equation above gives<br />

∫<br />

∫<br />

∫<br />

( f + g) + dμ − ( f + g) − dμ =<br />

∫<br />

f + dμ −<br />

∫<br />

f − dμ +<br />

∫<br />

g + dμ −<br />

g − dμ,<br />

where the left side is not of the form ∞ − ∞ because ( f + g) + ≤ f + + g + and<br />

( f + g) − ≤ f − + g − . The equation above can be rewritten as<br />

∫<br />

∫ ∫<br />

( f + g) dμ = f dμ + g dμ,<br />

Gottfried Leibniz (1646–1716)<br />

invented the symbol ∫ to denote<br />

completing the proof.<br />

integration in 1675.<br />

The next result resembles 3.8, but now the functions are allowed to be real valued.<br />

3.22 integration is order preserving<br />

Suppose (X, S, μ) is a measure space and f , g : X → R are S-measurable<br />

functions such that ∫ f dμ and ∫ g dμ are defined. Suppose also that f (x) ≤ g(x)<br />

for all x ∈ X. Then ∫ f dμ ≤ ∫ g dμ.<br />

Proof The cases where ∫ f dμ = ±∞ or ∫ g dμ = ±∞ are left to the reader. Thus<br />

we assume that ∫ | f | dμ < ∞ and ∫ |g| dμ < ∞.<br />

The additivity (3.21) and homogeneity (3.20 with c = −1) of integration imply<br />

that<br />

∫ ∫ ∫<br />

g dμ − f dμ = (g − f ) dμ.<br />

The last integral is nonnegative because g(x) − f (x) ≥ 0 for all x ∈ X.<br />

<strong>Measure</strong>, <strong>Integration</strong> & <strong>Real</strong> <strong>Analysis</strong>, by Sheldon Axler

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