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Measure, Integration & Real Analysis, 2021a

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Section 2B Measurable Spaces and Functions 27<br />

Now we come to some easy but important properties of σ-algebras.<br />

2.25 σ-algebras are closed under countable intersection<br />

Suppose S is a σ-algebra on a set X. Then<br />

(a) X ∈S;<br />

(b) if D, E ∈S, then D ∪ E ∈Sand D ∩ E ∈Sand D \ E ∈S;<br />

(c) if E 1 , E 2 ,...is a sequence of elements of S, then<br />

∞⋂<br />

k=1<br />

E k ∈S.<br />

Proof Because ∅ ∈Sand X = X \ ∅, the first two bullet points in the definition<br />

of σ-algebra (2.23) imply that X ∈S, proving (a).<br />

Suppose D, E ∈S. Then D ∪ E is the union of the sequence D, E, ∅, ∅,...of<br />

elements of S. Thus the third bullet point in the definition of σ-algebra (2.23) implies<br />

that D ∪ E ∈S.<br />

De Morgan’s Laws tell us that<br />

X \ (D ∩ E) =(X \ D) ∪ (X \ E).<br />

If D, E ∈S, then the right side of the equation above is in S; hence X \ (D ∩ E) ∈S;<br />

thus the complement in X of X \ (D ∩ E) is in S; in other words, D ∩ E ∈S.<br />

Because D \ E = D ∩ (X \ E), we see that if D, E ∈S, then D \ E ∈S,<br />

completing the proof of (b).<br />

Finally, suppose E 1 , E 2 ,...is a sequence of elements of S. De Morgan’s Laws<br />

tell us that<br />

∞⋂ ∞⋃<br />

X \ E k = (X \ E k ).<br />

k=1<br />

The right side of the equation above is in S. Hence the left side is in S, which implies<br />

that X \ (X \ ⋂ ∞<br />

k=1<br />

E k ) ∈S. In other words, ⋂ ∞<br />

k=1<br />

E k ∈S, proving (c).<br />

The word measurable is used in the terminology below because in the next section<br />

we introduce a size function, called a measure, defined on measurable sets.<br />

k=1<br />

2.26 Definition measurable space; measurable set<br />

• A measurable space is an ordered pair (X, S), where X is a set and S is a<br />

σ-algebra on X.<br />

• An element of S is called an S-measurable set, or just a measurable set if S<br />

is clear from the context.<br />

For example, if X = R and S is the set of all subsets of R that are countable or<br />

have a countable complement, then the set of rational numbers is S-measurable but<br />

the set of positive real numbers is not S-measurable.<br />

<strong>Measure</strong>, <strong>Integration</strong> & <strong>Real</strong> <strong>Analysis</strong>, by Sheldon Axler

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