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Measure, Integration & Real Analysis, 2021a

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48 Chapter 2 <strong>Measure</strong>s<br />

Thus<br />

|A ∪ G| ≥ ∣ ∣A ∪ ( m ⋃<br />

= |A| +<br />

n=1<br />

I n<br />

)∣ ∣<br />

m<br />

∑ l(I n ).<br />

n=1<br />

∞<br />

|A ∪ G| ≥|A| + ∑ l(I n )<br />

n=1<br />

≥|A| + |G|,<br />

completing the proof that |A ∪ G| = |A| + |G|.<br />

The next result shows that the outer measure of the disjoint union of two sets is<br />

what we expect if at least one of the two sets is closed.<br />

2.63 additivity of outer measure if one of the sets is closed<br />

Suppose A and F are disjoint subsets of R and F is closed. Then<br />

|A ∪ F| = |A| + |F|.<br />

Proof Suppose I 1 , I 2 ,...is a sequence of open intervals whose union contains A ∪ F.<br />

Let G = ⋃ ∞<br />

k=1<br />

I k . Thus G is an open set with A ∪ F ⊂ G. Hence A ⊂ G \ F, which<br />

implies that<br />

2.64 |A| ≤|G \ F|.<br />

Because G \ F = G ∩ (R \ F), we know that G \ F is an open set. Hence we can<br />

apply 2.62 to the disjoint union G = F ∪ (G \ F), getting<br />

|G| = |F| + |G \ F|.<br />

Adding |F| to both sides of 2.64 and then using the equation above gives<br />

|A| + |F| ≤|G|<br />

∞<br />

≤ ∑ l(I k ).<br />

k=1<br />

Thus |A| + |F| ≤|A ∪ F|, which implies that |A| + |F| = |A ∪ F|.<br />

Recall that the collection of Borel sets is the smallest σ-algebra on R that contains<br />

all open subsets of R. The next result provides an extremely useful tool for<br />

approximating a Borel set by a closed set.<br />

2.65 approximation of Borel sets from below by closed sets<br />

Suppose B ⊂ R is a Borel set. Then for every ε > 0, there exists a closed set<br />

F ⊂ B such that |B \ F| < ε.<br />

<strong>Measure</strong>, <strong>Integration</strong> & <strong>Real</strong> <strong>Analysis</strong>, by Sheldon Axler

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