06.09.2021 Views

Measure, Integration & Real Analysis, 2021a

Measure, Integration & Real Analysis, 2021a

Measure, Integration & Real Analysis, 2021a

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

244 Chapter 8 Hilbert Spaces<br />

8.61 Definition orthonormal basis<br />

An orthonormal family {e k } k∈Γ in a Hilbert space V is called an orthonormal<br />

basis of V if<br />

span {e k } k∈Γ = V.<br />

In addition to requiring orthonormality (which implies linear independence), the<br />

definition above differs from the definition of a basis by considering the closure of<br />

the span rather than the span. An important point to keep in mind is that despite the<br />

terminology, an orthonormal basis is not necessarily a basis in the sense of 6.54. In<br />

fact, if Γ is an infinite set and {e k } k∈Γ is an orthonormal basis of V, then {e k } k∈Γ is<br />

not a basis of V (see Exercise 9).<br />

8.62 Example orthonormal bases<br />

• For n ∈ Z + and k ∈{1, . . . , n}, let e k be the element of F n all of whose<br />

coordinates are 0 except the k th coordinate, which is 1:<br />

e k =(0,...,0,1,0,...,0).<br />

Then {e k } k∈{1,...,n} is an orthonormal basis of F n .<br />

• Let e 1 = ( 1 √3 ,<br />

1 √3 ,<br />

1 √3<br />

)<br />

, e2 = ( − 1 √<br />

2<br />

,<br />

1 √2 ,0 ) , and e 3 = ( 1 √6 ,<br />

1 √6 , − 2 √<br />

6<br />

)<br />

. Then<br />

{e k } k∈{1,2,3} is an orthonormal basis of F 3 , as you should verify.<br />

• The first three bullet points in 8.51 are examples of orthonormal families that are<br />

orthonormal bases. The exercises ask you to verify that we have an orthonormal<br />

basis in the first and second bullet points of 8.51. For the third bullet point<br />

(trigonometric functions), see Exercise 11 in Section 10D or see Chapter 11.<br />

The next result shows why orthonormal bases are so useful—a Hilbert space with<br />

an orthonormal basis {e k } k∈Γ behaves like l 2 (Γ).<br />

8.63 Parseval’s identity<br />

Suppose {e k } k∈Γ is an orthonormal basis of a Hilbert space Vand f , g ∈ V. Then<br />

(a)<br />

f = ∑ 〈 f , e k 〉e k ;<br />

k∈Γ<br />

(b) 〈 f , g〉 = ∑ 〈 f , e k 〉〈g, e k 〉;<br />

k∈Γ<br />

(c) ‖ f ‖ 2 = ∑ |〈 f , e k 〉| 2 .<br />

k∈Γ<br />

Proof The equation in (a) follows immediately from 8.58(b) and the definition of an<br />

orthonormal basis.<br />

<strong>Measure</strong>, <strong>Integration</strong> & <strong>Real</strong> <strong>Analysis</strong>, by Sheldon Axler

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!