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2.2.3 Udledning af Pt U<br />

Yt <br />

xt 1 <br />

Pt C Ct<br />

P t Y Pt 1 P t 1<br />

På samme måde kan følgende udledes:<br />

Heraf følger<br />

P t 1<br />

P t Y<br />

1<br />

<br />

Pt CCt Pt Y PY t <br />

1<br />

<br />

Pt 1<br />

P t C<br />

1t t w w<br />

Pt U 1 tt w 1 <br />

w<br />

A 1 <br />

Ct <br />

xt 5 <br />

<br />

Ct <br />

1 <br />

1<br />

P t C<br />

1t t w w<br />

Pt c<br />

w1 tt w <br />

Pt U Ut<br />

<br />

1E<br />

P t C<br />

1t t w w<br />

Ft<br />

Ct<br />

<br />

1 <br />

Pt C 1 tt w w 1t t w w<br />

P t C<br />

Pt C<br />

Idet der gælder, at Pt U Ut Mt<br />

Ct <br />

Ft <br />

P t C<br />

1t t w w<br />

Pt UUt <br />

E<br />

1<br />

Pt C w1 tt w <br />

Pt C<br />

P t C<br />

w1t t w <br />

Mt<br />

Mt<br />

<br />

E<br />

1<br />

1<br />

E<br />

E<br />

<br />

1<br />

E<br />

<br />

1 1E<br />

E<br />

1E<br />

22<br />

23<br />

24<br />

25<br />

Ft 26<br />

1<br />

<br />

E<br />

1 tt w w<br />

w1t t w <br />

P t u<br />

1<br />

<br />

E<br />

w1 tt w <br />

2.3 Opsummering<br />

Dvs. løsningen til forbrugerens problem er givet ved:<br />

-58-<br />

28<br />

29<br />

30<br />

31

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