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Alternative Support Systems for Cantilever - National Transportation ...

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Throat := .707⋅Weld_Size ϕRn_weld := ϕweld⋅Throat⋅FW ϕRn_weld 5.568 kip<br />

= ⋅<br />

in<br />

ϕRn_yield := .6⋅fy.pipe⋅twall.embed.pipe ϕRn_yield 9.45 kip<br />

= ⋅<br />

in<br />

ϕRn_rupture := .45⋅fu.pipe⋅twall.embed.pipe ϕRn_rupture 9.787 kip<br />

= ⋅<br />

in<br />

ϕRn := min( ϕRn_weld, ϕRn_yield, ϕRn_rupture) ϕRn 5.568 kip<br />

= ⋅<br />

in<br />

Required_Length_Plate :=<br />

Vweld.flex ϕRn Required_Length_Plate = 32.044⋅in Check_Length := "Sufficient" if π⋅Diameterembed.pipe "Not Sufficient" otherwise<br />

Embedded Pipe and Flexure Plate Design<br />

Concrete Pedestal Rein<strong>for</strong>cement<br />

Step 5) Concrete Pedestal Rein<strong>for</strong>cement<br />

Given<br />

Diametershaft = 42⋅in fy.rebar := 50ksi<br />

Lshaft = 12 ft<br />

f'c = 5.5⋅ksi Vu = 9.04 kip<br />

Tu = 198.88 ft·kip<br />

Mu = 165.34 ft·kip<br />

Rein<strong>for</strong>cement <strong>for</strong> Flexure<br />

Determine properties of flexural rein<strong>for</strong>cement<br />

Numberflex.rebar := Nolong.rebar = 11<br />

2<br />

Aflex.rebar := .25π ⋅ ⋅Diameterflex.rebar<br />

Assume 8 of the 11 bars yield<br />

nflex.yield := 8<br />

⎛<br />

⎜<br />

⎝<br />

ceil Required_Length_Plate<br />

⎟⋅in = 33⋅in in ⎠<br />

( ) ≥ Required_Length_Plate<br />

Diameterhoop.rebar := .500in<br />

R := .5Diametershaft = 21⋅in Diameterflex.rebar := 1.375in<br />

Diameterrebar.circle := 27.5in<br />

192<br />

Check_Length = "Sufficient"<br />

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