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Ordinary Differential Equations 191<br />

well-posed. This means that <strong>it</strong> adm<strong>it</strong>s a unique weak solution U ∈ X. We remark that<br />

two solutions of (9.3.1) which differ on a set of measure zero are in the same class of<br />

equivalence in X.<br />

We first introduce some notation. Consider the bilinear form Bw : X ×X → R defined<br />

as follows:<br />

<br />

(9.3.2) Bw(ψ,φ) :=<br />

ψ<br />

I<br />

′ (φw) ′ dx, ∀ψ,φ ∈ X.<br />

The mapping Bw is linear in each argument (this justifies the term bilinear). We also<br />

define the linear operator Fw : X → R according to<br />

<br />

(9.3.3) Fw(φ) :=<br />

I<br />

fφw dx, ∀φ ∈ X.<br />

W<strong>it</strong>h the above defin<strong>it</strong>ions we restate (9.3.1). We are concerned w<strong>it</strong>h finding U ∈ X<br />

such that<br />

(9.3.4) Bw(U,φ) = Fw(φ), ∀φ ∈ X.<br />

The answer to our question relies on the following general result.<br />

Theorem 9.3.1 (Lax & Milgram) - Let X be a Hilbert space. Let B : X × X → R<br />

be a bilinear form and F : X → R be a linear operator. Let us assume that there exist<br />

three pos<strong>it</strong>ive constants C1,C2,C3 such that<br />

(9.3.5) |B(ψ,φ)| ≤ C1 ψX φX, ∀ψ,φ ∈ X,<br />

(9.3.6) B(ψ,ψ) ≥ C2 ψ 2 X, ∀ψ ∈ X,<br />

(9.3.7) |F(φ)| ≤ C3 φX, ∀φ ∈ X.

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