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84 Polynomial Approximation of Differential Equations<br />

5.4 Weak derivatives<br />

We recall that the space Ck ( Ī), where k ≥ 1 is an integer, is given by the functions<br />

whose derivatives, of order less or equal to k, exist and are continuous in Ī. Following<br />

section 5.3, when I is bounded, a norm for Ck ( Ī) is obtained by setting<br />

(5.4.1) u C k (Ī) := u C 0 (Ī) +<br />

k<br />

<br />

<br />

<br />

d<br />

<br />

mu dxm <br />

<br />

<br />

m=1<br />

C 0 (Ī)<br />

, u ∈ C k ( Ī), k ≥ 1.<br />

W<strong>it</strong>h this norm C k ( Ī), k ≥ 1, is a complete space. In particular, when u ∈ Ck ( Ī),<br />

∀k ∈ N, we say that u ∈ C∞ ( Ī). We are mainly concerned w<strong>it</strong>h a particular subspace<br />

of C∞ ( Ī). This is denoted by C∞ 0 (I) and consists of all the functions φ ∈ C∞ ( Ī) such<br />

that there exists a closed and bounded interval strictly included in I, outside of which φ<br />

vanishes. Therefore, since I is open, any function in C ∞ 0 (I) is zero in a neighborhood of<br />

the possible boundary points of I. Therefore, all the derivatives of a function in C ∞ 0 (I)<br />

still belong to C ∞ 0 (I).<br />

Up to this point, we only considered subspaces of the set of continuous functions.<br />

This is against the policy of expanding our functional spaces. We now give meaning<br />

to the differential calculus of measurable functions by introducing the concept of weak<br />

derivative. A Lebesgue integrable function u is differentiable in a weak sense, if there<br />

exists another integrable function v such that<br />

<br />

(5.4.2)<br />

uφ ′ <br />

dx = −<br />

I<br />

vφ dx, ∀φ ∈ C<br />

I<br />

∞ 0 (I).<br />

The function v is the weak derivative of u which is indicated using classical notation.<br />

This defin<strong>it</strong>ion is not in conflict w<strong>it</strong>h the usual one. Actually, we claim that, if u ∈ C 1 ( Ī),<br />

then v ∈ C0 ( Ī) is exactly the standard derivative of u. To prove this statement, we just<br />

integrate the left-hand side of (5.4.2) by parts. Recalling the vanishing cond<strong>it</strong>ions on φ,<br />

we obtain as requested<br />

<br />

(5.4.3)<br />

(u<br />

I<br />

′ − v)φ dx = 0, ∀φ ∈ C ∞ 0 (I) =⇒ v ≡ u ′ .<br />

The implication in (5.4.3) can be proven w<strong>it</strong>h a l<strong>it</strong>tle knowledge of basic calculus.

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