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Untitled - Cdm.unimo.it

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208 Polynomial Approximation of Differential Equations<br />

(9.5.2) X ≡ H 1 0,v(I) := {φ |φ ∈ H 1 v(I), φ(0) = 0}.<br />

According to section 5.7, the norm in X is given by φX := <br />

I φ2vdx + <br />

∀φ ∈ X. Then, for g ∈ L2 v(I), we are concerned w<strong>it</strong>h finding U ∈ X such that<br />

(9.5.3)<br />

+∞<br />

U<br />

0<br />

′ (φv) ′ +∞<br />

dx + µ<br />

0<br />

Uφv dx =<br />

+∞<br />

0<br />

I [φ′ ] 2 vdx<br />

gφv dx, ∀φ ∈ X.<br />

W<strong>it</strong>h the same arguments of section 9.3, using the Lax-Milgram theorem, we get exis-<br />

tence and uniqueness of a weak solution of (9.5.3), provided the parameter µ is larger<br />

than 1<br />

2 max{1, 1<br />

1−α }. The crucial part of the proof is to show coerciveness (see (9.3.6)).<br />

This follows by virtue of lemma 8.2.7.<br />

One checks that U ∈ X implies that limx→+∞ U(x) = 0, and the decay is exponential.<br />

Therefore, due to theorem 6.1.4, we have the requis<strong>it</strong>es to approximate the solution of<br />

problem (9.5.3) by Laguerre functions (see section 6.7). To this end, we introduce the<br />

subspace S 0 n := {φ| φ ∈ Sn, φ(0) = 0} ⊂ X.<br />

For example, when g ∈ C0 ( Ī), we discretize (9.5.3) as follows. For any n ≥ 2, we seek<br />

Pn ∈ S0 n−1 such that<br />

+∞<br />

(9.5.4)<br />

0<br />

P ′ n(φv) ′ +∞<br />

dx + µ Pnφv dx =<br />

0<br />

+∞<br />

0<br />

( Ĩ∗ v,ng)φv dx, ∀φ ∈ S 0 n−1.<br />

The interpolation operator Ĩ∗ v,n : C 0 ( Ī) → Sn−1, n ≥ 2, is defined by the relation<br />

Ĩ ∗ v,ng := [ Ĩw,n(ge x )]e −x , ∀g ∈ C 0 ( Ī) (see also section 6.7), where Ĩw,n, n ≥ 1, is the<br />

Laguerre Gauss-Radau interpolation operator (see section 3.3). We now apply theorem<br />

9.4.1. Estimating the error g − Ĩ∗ v,ng L 2 v (I), one deduces that Pn converges to U, as n<br />

tends to infin<strong>it</strong>y, in the norm of the space X. The convergence is also uniform because<br />

of the inequal<strong>it</strong>y<br />

(9.5.5) sup<br />

x∈I<br />

|φ(x)e x/2 | ≤ C φX, ∀φ ∈ X.<br />

The next step is to determine the solution to (9.5.4). We consider the subst<strong>it</strong>utions:<br />

pn(x) := Pn(x)ex , x ∈ Ī, n ≥ 2, and f(x) := g(x)ex , x ∈ Ī. Therefore, integration by<br />

parts allows us to wr<strong>it</strong>e (note that the boundary terms are vanishing):<br />

1<br />

2 ,

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