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Functional Spaces 79<br />

We are now ready to give the defin<strong>it</strong>ion of a Lebesgue measurable set. The subset J ⊂ Ī<br />

is measurable if and only if<br />

(5.1.3) µ ∗ (J) = µ( Ī) − µ∗ ( Ī − J).<br />

Then we set µ(J) := µ ∗ (J). The idea is the following. The term on the left-hand<br />

side of (5.1.3) is obtained by approximating J from outside w<strong>it</strong>h families of intervals.<br />

The term on the right-hand side represents in some sense an approximation from inside.<br />

When both the estimates coincide, then J is measurable.<br />

It is possible to show that the union and intersection of a fin<strong>it</strong>e number of measurable<br />

sets are still measurable. Moreover, and this is the main improvement w<strong>it</strong>h respect to<br />

Riemann measure theory, union and intersection of a countable family of measurable<br />

sets are still measurable. If the sets Ji, i ∈ N, are measurable and disjoint, then<br />

(5.1.4) µ<br />

∞<br />

i=0<br />

Ji<br />

<br />

=<br />

∞<br />

i=0<br />

µ(Ji).<br />

For instance, the set of rational numbers J = Q ∩Ī, is not Riemann measurable. Being<br />

the union of a countable collection of points, J is Lebesgue measurable and by (5.1.4)<br />

µ(J) = 0. If I is an unbounded interval, then J ⊂<br />

measurable for any bounded interval K ⊂<br />

also take the value +∞.<br />

Ī is measurable when J ∩ K is<br />

Ī. In this s<strong>it</strong>uation we assume that µ can<br />

We can now introduce the concept of measurable function. A function f : Ī → R<br />

is measurable when the set {x ∈<br />

Ī| f(x) < γ} is measurable for any γ ∈ R. It is<br />

possible to prove that the sum and the product of two measurable functions are still<br />

measurable.<br />

A measurable function that assumes a fin<strong>it</strong>e or countable set of values in<br />

Ī, is called<br />

simple function. Any bounded measurable function f can be represented as a uniform<br />

lim<strong>it</strong> of simple functions fn, n ∈ N (this means that limn→∞ sup x∈I |fn(x)−f(x)| = 0).

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