14.03.2014 Views

Quality and Reliability Methods - SAS

Quality and Reliability Methods - SAS

Quality and Reliability Methods - SAS

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

106 Cumulative Sum Control Charts Chapter 6<br />

Formulas for CUSUM Charts<br />

Two-Sided Cusum Schemes<br />

If the cusum scheme is two-sided, the cumulative sum S t plotted for the t th subgroup is<br />

S t = S t - 1 +z t<br />

for t = 1, 2,..., n. Here S 0 =0, <strong>and</strong> the term z t is calculated as<br />

z t<br />

= ( X t – μ 0<br />

) ⁄ ( σ ⁄ n t<br />

)<br />

where X is the t th subgroup average, <strong>and</strong> n t is the t th t<br />

subgroup sample size. If the subgroup samples consist<br />

of individual measurements x t , the term z t simplifies to<br />

z t = (x t – μ 0 )/σ<br />

Since the first equation can be rewritten as<br />

S t<br />

t t<br />

= z i<br />

= ( X i – μ 0<br />

) ⁄ σ<br />

Xi<br />

i = 1 i = 1<br />

the sequence S t cumulates st<strong>and</strong>ardized deviations of the subgroup averages from the target mean μ 0 .<br />

In many applications, the subgroup sample sizes n i are constant (n i = n), <strong>and</strong> the equation for S t can be<br />

simplified.<br />

S t<br />

t<br />

= ( 1 ⁄ σ ) X<br />

( X i – μ 0<br />

) =<br />

i = 1<br />

( n ⁄ σ) ( X i – μ 0<br />

)<br />

i = 1<br />

In some applications, it might be preferable to compute S t as<br />

t<br />

S t<br />

= ( X i – μ 0<br />

)<br />

i = 1<br />

t<br />

<br />

which is scaled in the same units as the data. In this case, the procedure rescales the V-mask parameters h<br />

<strong>and</strong> k to h' = hσ ⁄ n <strong>and</strong> k' = kσ ⁄ n , respectively. Some authors use the symbols F for k' <strong>and</strong> H for h'.<br />

If the process is in control <strong>and</strong> the mean μ is at or near the target μ 0 , the points will not exhibit a trend since<br />

positive <strong>and</strong> negative displacements from μ 0 tend to cancel each other. If μ shifts in the positive direction,<br />

the points exhibit an upward trend, <strong>and</strong> if μ shifts in the negative direction, the points exhibit a downward<br />

trend.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!