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Introduction to SAT II Physics - FreeExamPapers

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If we know our formulas, this problem is easy. The heat in<strong>to</strong> the system is<br />

= 80 J, and the<br />

heat out of the system is = 20 J. The efficiency, then, is: 1 – 20 ⁄ 80 = 0.75 = 75% .<br />

Key Formulas<br />

Conversion<br />

between<br />

Fahrenheit and<br />

Celsius<br />

Conversion<br />

between Celsius<br />

and Kelvin<br />

Relationship<br />

between Heat<br />

and<br />

Temperature<br />

Coefficient of<br />

Linear<br />

Expansion<br />

Coefficient of<br />

Volume<br />

Expansion<br />

Ideal Gas Law<br />

Boyle’s Law<br />

Charles’s Law<br />

First Law of<br />

Thermodynami<br />

cs<br />

Efficiency of a<br />

Heat Engine<br />

197

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