15.04.2014 Views

Introduction to SAT II Physics - FreeExamPapers

Introduction to SAT II Physics - FreeExamPapers

Introduction to SAT II Physics - FreeExamPapers

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

Circuits<br />

Most <strong>SAT</strong> <strong>II</strong> <strong>Physics</strong> questions on circuits will show you a circuit diagram and ask you<br />

questions about the current, resistance, or voltage at different points in the circuit. These<br />

circuits will usually consist of a power source and one or more resis<strong>to</strong>rs arranged in<br />

parallel or in series. You will occasionally encounter other circuit elements, such as a<br />

voltmeter, an ammeter, a fuse, or a capaci<strong>to</strong>r. Reading the diagrams is not difficult, but<br />

since there will be a number of questions on the test that rely on diagrams, it’s important<br />

that you master this skill. Here’s a very simple circuit diagram:<br />

Zigzags represent resis<strong>to</strong>rs, and a pair of parallel, unequal lines represents a battery cell.<br />

The longer line is the positive terminal and the shorter line is the negative terminal. That<br />

means the current flows from the longer line around the circuit <strong>to</strong> the shorter line. In the<br />

diagram above, the current flows counterclockwise. Often, more than one set of unequal<br />

parallel lines are arranged <strong>to</strong>gether; this just signifies a number of battery cells arranged<br />

in series.<br />

Example<br />

In the diagram above, = 6 V and R = 12 . What is the current in the circuit and what is<br />

the power dissipated in the resis<strong>to</strong>r?<br />

You don’t really need <strong>to</strong> refer <strong>to</strong> the diagram in order <strong>to</strong> solve this problem. As long as<br />

you know that there’s a circuit with a six-volt battery and a 12-ohm resis<strong>to</strong>r, you need<br />

only apply Ohm’s Law and the formula for power.<br />

Since I = V/R, the current is:<br />

The power is:<br />

Resis<strong>to</strong>rs in Series<br />

Two resis<strong>to</strong>rs are in series when they are arranged one after another on the circuit, as in<br />

the diagram below. The same amount of current flows first through one resis<strong>to</strong>r and then<br />

the other, since the current does not change over the length of a circuit.<br />

224

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!