12.07.2015 Views

Simple Nature - Light and Matter

Simple Nature - Light and Matter

Simple Nature - Light and Matter

SHOW MORE
SHOW LESS
  • No tags were found...

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

stroke are both executed in straight lines. Since the forces are inopposite directions, one is positive <strong>and</strong> one is negative. The cyclist’stotal force on the crank set is zero, but the work done isn’t zero. Wehave to add the work done by each stroke, W = F 1 ∆x 1 + F 2 ∆x 2 .(I’m pretending that both forces are constant, so we don’t have todo integrals.) Both terms are positive; one is a positive numbermultiplied by a positive number, while the other is a negative timesa negative.This might not seem like a big deal — just remember not to usethe total force — but there are many situations where the total forceis all we can measure. The ultimate example is heat conduction.Heat conduction is not supposed to be counted as a form of work,since it occurs without a force. But at the atomic level, there areforces, <strong>and</strong> work is done by one atom on another. When you hold ahot potato in your h<strong>and</strong>, the transfer of heat energy through yourskin takes place with a total force that’s extremely close to zero.At the atomic level, atoms in your skin are interacting electricallywith atoms in the potato, but the attractions <strong>and</strong> repulsions addup to zero total force. It’s just like the cyclist’s feet acting on thepedals, but with zillions of forces involved instead of two. There isno practical way to measure all the individual forces, <strong>and</strong> thereforewe can’t calculate the total energy transferred.To summarize, ∑ F j dx j is a correct way of calculating work,where F j is the individual force acting on particle j, which moves adistance dx j . However, this is only useful if you can identify all theindividual forces <strong>and</strong> determine the distance moved at each point ofcontact. For convenience, I’ll refer to this as the work theorem. (Itdoesn’t have a st<strong>and</strong>ard name.)There is, however, something useful we can do with the totalforce. We can use it to calculate the part of the work done on anobject that consists of a change in the kinetic energy it has due tothe motion of its center of mass. The proof is essentially the sameas the proof on p. 161, except that now we don’t assume the forceis acting on a single particle, so we have to be a little more delicate.Let the object consist of n particles. Its total kinetic energy isK = ∑ nj=1 (1/2)m jvj 2 , but this is what we’ve already realized can’tbe calculated using the total force. The kinetic energy it has due tomotion of its center of mass isK cm = 1 2 m totalv 2 cm .Figure r shows some examples of the distinction between K cm <strong>and</strong>164 Chapter 3 Conservation of Momentum

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!