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Simple Nature - Light and Matter

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Problem 22.22 The sun turns on its axis once every 26.0 days. Its massis 2.0 × 10 30 kg <strong>and</strong> its radius is 7.0 × 10 8 m. Assume it is a rigidsphere of uniform density.(a) What is the sun’s angular momentum?In a few billion years, astrophysicists predict that the sun will useup all its sources of nuclear energy, <strong>and</strong> will collapse into a ball ofexotic, dense matter known as a white dwarf. Assume that its radiusbecomes 5.8 × 10 6 m (similar to the size of the Earth.) Assume itdoes not lose any mass between now <strong>and</strong> then. (Don’t be fooledby the photo, which makes it look like nearly all of the star wasthrown off by the explosion. The visually prominent gas cloud isactually thinner than the best laboratory vacuum ever produced onearth. Certainly a little bit of mass is actually lost, but it is not atall unreasonable to make an approximation of zero loss of mass aswe are doing.)(b) What will its angular momentum be?(c) How long will it take to turn once on its axis?√√Problem 2323 Give a numerical comparison of the two molecules’ momentsof inertia for rotation in the plane of the page about their centersof mass.24 A yo-yo of total mass m consists of two solid cylindersof radius R, connected by a small spindle of negligible mass <strong>and</strong>radius r. The top of the string is held motionless while the stringunrolls from the spindle. Show that the acceleration of the yo-yo isg/(1 + R 2 /2r 2 ).25 Show that a sphere of radius R that is rolling without slippinghas angular momentum <strong>and</strong> momentum in the ratio L/p = (2/5)R.26 Suppose a bowling ball is initially thrown so that it has noangular momentum at all, i.e., it is initially just sliding down thelane. Eventually kinetic friction will bring its angular velocity up tothe point where it is rolling without slipping. Show that the finalvelocity of the ball equals 5/7 of its initial velocity. You’ll need theresult of problem 25.27 Find the angular momentum of a particle whose position isr = 3ˆx−ŷ +ẑ (in meters) <strong>and</strong> whose momentum is p = −2ˆx+ŷ +ẑ√(in kg·m/s).292 Chapter 4 Conservation of Angular Momentum

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