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Simple Nature - Light and Matter

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o / Magnetic forces cause abeam of electrons to move in acircle.p / You can’t isolate the poles of amagnet by breaking it in half.q / A magnetic dipole is madeout of other dipoles, not out ofmonopoles.A circular orbit example 4The magnetic force is always perpendicular to the motion of theparticle, so it can never do any work, <strong>and</strong> a charged particle movingthrough a magnetic field does not experience any change inits kinetic energy: its velocity vector can change its direction, butnot its magnitude. If the velocity vector is initially perpendicularto the field, then the curve of its motion will remain in the planeperpendicular to the field, so the magnitude of the magnetic forceon it will stay the same. When an object experiences a force withconstant magnitude, which is always perpendicular to the directionof its motion, the result is that it travels in a circle.Figure o shows a beam of electrons in a spherical vacuum tube.In the top photo, the beam is emitted near the right side of thetube, <strong>and</strong> travels straight up. In the bottom photo, a magnetic fieldhas been imposed by an electromagnet surrounding the vacuumtube; the ammeter on the right shows that the current through theelectromagnet is now nonzero. We observe that the beam is bentinto a circle.self-check AInfer the direction of the magnetic field. Don’t forget that the beam ismade of electrons, which are negatively charged! ⊲ Answer, p. 926Homework problem 12 is a quantitative analysis of circular orbits.A velocity filter example 5Suppose you see the electron beam in figure o, <strong>and</strong> you want todetermine how fast the electrons are going. You certainly can’tdo it with a stopwatch! Physicists may also encounter situationswhere they have a beam of unknown charged particles, <strong>and</strong> theydon’t even know their charges. This happened, for instance, whenalpha <strong>and</strong> beta radiation were discovered. One solution to thisproblem relies on the fact that the force experienced by a chargedparticle in an electric field, F E = qE, is independent of its velocity,but the force due to a magnetic field, F B = qv × B, isn’t. Onecan send a beam of charged particles through a space containingboth an electric <strong>and</strong> a magnetic field, setting up the fields so thatthe two forces will cancel out perfectly for a certain velocity. Notethat since both forces are proportional to the charge of the particles,the cancellation is independent of charge. Such a velocityfilter can be used either to determine the velocity of an unknownbeam or particles, or to select from a beam of particles only thosehaving velocities within a certain desired range. Homework problem7 is an analysis of this application.11.1.4 No magnetic monopolesIf you could play with a h<strong>and</strong>ful of electric dipoles <strong>and</strong> a h<strong>and</strong>fulof bar magnets, they would appear very similar. For instance, a pairof bar magnets wants to align themselves head-to-tail, <strong>and</strong> a pair of656 Chapter 11 Electromagnetism

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