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Simple Nature - Light and Matter

Simple Nature - Light and Matter

Simple Nature - Light and Matter

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Although the equation λ/d = sin θ/m is only valid for a doubleslit, it is can still be a guide to our thinking even if we are observingdiffraction of light by a virus or a flea’s leg: it is always true that(1) large values of λ/d lead to a broad diffraction pattern, <strong>and</strong>(2) diffraction patterns are repetitive.In many cases the equation looks just like λ/d = sin θ/m butwith an extra numerical factor thrown in, <strong>and</strong> with d interpreted assome other dimension of the object, e.g., the diameter of a piece ofwire.s / A triple slit.t / A double-slit diffraction pattern(top), <strong>and</strong> a pattern made by fiveslits (bottom).12.5.6 RepetitionSuppose we replace a double slit with a triple slit, s. We canthink of this as a third repetition of the structures that were presentin the double slit. Will this device be an improvement over thedouble slit for any practical reasons?The answer is yes, as can be shown using figure u. For easeof visualization, I have violated our usual rule of only consideringpoints very far from the diffracting object. The scale of the drawingis such that a wavelengths is one cm. In u/1, all three waves travelan integer number of wavelengths to reach the same point, so thereis a bright central spot, as we would expect from our experiencewith the double slit. In figure u/2, we show the path lengths toa new point. This point is farther from slit A by a quarter of awavelength, <strong>and</strong> correspondingly closer to slit C. The distance fromslit B has hardly changed at all. Because the paths lengths traveledfrom slits A <strong>and</strong> C differ by half a wavelength, there will be perfectdestructive interference between these two waves. There is still someuncanceled wave intensity because of slit B, but the amplitude willbe three times less than in figure u/1, resulting in a factor of 9decrease in brightness. Thus, by moving off to the right a little, wehave gone from the bright central maximum to a point that is quitedark.Now let’s compare with what would have happened if slit C hadbeen covered, creating a plain old double slit. The waves comingfrom slits A <strong>and</strong> B would have been out of phase by 0.23 wavelengths,but this would not have caused very severe interference. The pointin figure u/2 would have been quite brightly lit up.To summarize, we have found that adding a third slit narrowsdown the central fringe dramatically. The same is true for all theother fringes as well, <strong>and</strong> since the same amount of energy is con-790 Chapter 12 Optics

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