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Simple Nature - Light and Matter

Simple Nature - Light and Matter

Simple Nature - Light and Matter

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26 The first step in the proof of Ampère’s law on page 675 is toshow that Ampère’s law holds in the case shown in figure f/1, wherea circular Ampèrian loop is centered on a long, straight wire that isperpendicular to the plane of the loop. Carry out this calculation,using the result for the field of a wire that was established withoutusing Ampère’s law.27 A certain region of space has a magnetic field given by B =bxŷ. Find the electric current flowing through the square defined√by z = 0, 0 ≤ x ≤ a, <strong>and</strong> 0 ≤ y ≤ a.28 Perform a calculation similar to the one in problem 54, butfor a logarithmic spiral, defined by r = we uθ , <strong>and</strong> show that thefield is B = (kI/c 2 u)(1/a − 1/b). Note that the solution to problem54 is given in the back of the book.29 (a) For the geometry described in example 8 on page 661,find the field at a point the lies in the plane of the wires, but notbetween the wires, at a distance b from the center line. Use thesame technique as in that example.(b) Now redo the calculation using the technique demonstrated onpage 666. The integrals are nearly the same, but now the reasoningis reversed: you already know β = 1, <strong>and</strong> you want to find anunknown field. The only difference in the integrals is that you aretiling a different region of the plane in order to mock up the currentsin the two wires. Note that you can’t tile a region that containsa point of interest, since the technique uses the field of a distant√dipole.30 (a) A long, skinny solenoid consists of N turns of wirewrapped uniformly around a hollow cylinder of length l <strong>and</strong> crosssectionalarea A. Find its inductance.√(b) Show that your answer has the right units to be an inductance.A nautilus shell is approximatelya logarithmic spiral, of thetype in problem 28.31 Consider two solenoids, one of which is smaller so that itcan be put inside the other. Assume they are long enough to actlike ideal solenoids, so that each one only contributes significantlyto the field inside itself, <strong>and</strong> the interior fields are nearly uniform.Consider the configuration where the small one is partly inside <strong>and</strong>partly hanging out of the big one, with their currents circulating inthe same direction. Their axes are constrained to coincide.(a) Find the difference in the magnetic energy between the configurationwhere the solenoids are separate <strong>and</strong> the configuration wherethe small one is inserted into the big one. Your equation will includethe length x of the part of the small solenoid that is insidethe big one, as well as other relevant variables describing the two√solenoids.(b) Based on your answer to part a, find the force acting between√the solenoids.Problem 32.Problems 723

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