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Simple Nature - Light and Matter

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Page 224, problem 37: (a) Spring constants in parallel add, so the spring constant has tobe proportional to the cross-sectional area. Two springs in series give half the spring constant,three springs in series give 1/3, <strong>and</strong> so on, so the spring constant has to be inversely proportionalto the length. Summarizing, we have k ∝ A/L.(b) With the Young’s modulus, we have k = (A/L)E.The spring constant has units of N/m, sothe units of E would have to be N/m 2 .Page 226, problem 44: By conservation of momentum, the total momenta of the pieces afterthe explosion is the same as the momentum of the firework before the explosion. However, thereis no law of conservation of kinetic energy, only a law of conservation of energy. The chemicalenergy in the gunpowder is converted into heat <strong>and</strong> kinetic energy when it explodes. All we cansay about the kinetic energy of the pieces is that their total is greater than the kinetic energybefore the explosion.Page 226, problem 45: Let m be the mass of the little puck <strong>and</strong> M = 2.3m be the massof the big one. All we need to do is find the direction of the total momentum vector beforethe collision, because the total momentum vector is the same after the collision. Given the twocomponents of the momentum vector p x = mv <strong>and</strong> p y = Mv, the direction of the vector istan −1 (p y /p x ) = 23 ◦ counterclockwise from the big puck’s original direction of motion.Page 229, problem 62: We want to find out about the velocity vector v BG of the bulletrelative to the ground, so we need to add Annie’s velocity relative to the ground v AG to thebullet’s velocity vector v BA relative to her. Letting the positive x axis be east <strong>and</strong> y north, wehave<strong>and</strong>v BA,x = (140 mi/hr) cos 45 ◦= 100 mi/hrv BA,y = (140 mi/hr) sin 45 ◦v AG,x = 0= 100 mi/hrv AG,y = 30 mi/hr .The bullet’s velocity relative to the ground therefore has components<strong>and</strong>v BG,x = 100 mi/hrv BG,y = 130 mi/hr .Its speed on impact with the animal is the magnitude of this vector√|v BG | = (100 mi/hr) 2 + (130 mi/hr) 2= 160 mi/hr(rounded off to two significant figures).934 Chapter Appendix 4: Hints <strong>and</strong> Solutions

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