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Lecture Notes for Analog Electronics - The Electronic Universe ...

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We see that IC is not intrinsically a function of IB, but rather is controlled by VBE. For<br />

this reason, and others, it is often stated that transistor gain is really a transconductance<br />

gain. This means that it takes a voltage input and converts it to a current output. So we<br />

write, in general,<br />

gm = iout/vin<br />

as the transconductance gain. We then recover voltage gain by multiplying gm by the resistor<br />

at the output which converts the output current to a voltage. For example, <strong>for</strong> the commonemitter<br />

amplifier we have iout = −vin/RE and<br />

G = gmRC = −RC/RE<br />

as be<strong>for</strong>e.<br />

<strong>The</strong> base-emitter “diode” implies a relationship between IB and VBE of the <strong>for</strong>m VBE =<br />

V0 ln(IB/I0), where V0 ≈ 0.6 VandI0is a constant. If this <strong>for</strong>m <strong>for</strong> VBE is plugged into Eqn.<br />

31, we recover our previous relationship IC = βIB, where the current gain β is a combination<br />

of the various factors which are slowly-varying functions of temperature and currents.<br />

Another consequence of Ebers-Moll equation is that we see where the intrinsic emitter<br />

resistance re, which we introduced last time, comes from. By definition,<br />

1/re = iE/vBE ≈ iC/vBE = dIC<br />

From Eqn. 31, the derivative is simply IC/VT .Sowehave<br />

where VT is again as above.<br />

5.9.2 <strong>The</strong> Current Mirror<br />

re=VT/IC<br />

dVBE<br />

Figure 28 shows a very commonly used current source circuit known as the current mirror.<br />

Understanding its principle of operation requires the Ebers-Moll equation. <strong>The</strong> “programming<br />

current” IP defines the collector current of the left-hand transistor. (<strong>The</strong> base<br />

currents should be negligibly small.) From the Ebers-Moll equation, this collector current<br />

then uniquely determines VBE. <strong>The</strong> collector-base connection transfers this well-defined base<br />

voltage to the collector, thus maintaining the voltage drop across the programming resistor.<br />

<strong>The</strong> right-hand transistor is “matched” to the left-hand one. That is, the pair were manufactured<br />

together to have nearly identical properties. So this right-hand transistor assumes<br />

a nearly identical collector current to that which is programmed. Thus the load current<br />

becomes IL = IP . Besides transferring the program current to a load at another point of<br />

the circuit, the current mirror also has the advantage of having a larger range of compliance<br />

than the standard single-transistor current source we studied earlier.<br />

5.9.3 Other Non-ideal Effects<br />

<strong>The</strong> following represent some of the important departures from ideal transistor behavior:<br />

• VBE = VBE(T ). As discussed above, the base-emitter “diode” includes a Boltzmann<br />

factor temperature dependence. This can be linearized, as given in the text, to yield<br />

approximately<br />

∆VBE<br />

∆T ≈−2.1×10−3 V/ ◦ C<br />

32<br />

.<br />

(32)

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