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Electronic Devices and Amplifier Circuits

Electronic Devices and Amplifier Circuits - Orchard Publications

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Chapter 1 Basic <strong>Electronic</strong> Concepts <strong>and</strong> SignalsFrom Figure 1.16 we observe that all poles, denoted as , lie on the left−h<strong>and</strong> half−plane <strong>and</strong>thus the system is stable. The location of the zeros, denoted as , is immaterial.b. We use the MATLAB exp<strong>and</strong>(s) symbolic function to express the numerator <strong>and</strong> denominatorof Gs ( ) in polynomial formsyms s; n=exp<strong>and</strong>((s−1)*(s^2+2*s+5)), d=exp<strong>and</strong>((s+2)*(s^2+6*s+25))n = s^3+s^2+3*s-5d = s^3+s^2+3*s-5<strong>and</strong> thusGs ( )For this example we are interested in the magnitude only so we will use the scriptnum=3*[1 1 3 −5]; den=[1 8 37 50]; sys=tf(num,den);...w=logspace(0,2,100); bodemag(sys,w); gridThe magnitude plot is shown in Figure 1.17.3s ( 3 + s 2 + 3s – 5)= --------------------------------------------------( s 3 + 8s 2 + 37s + 50)Frequency (rad/sec, log scale)Figure 1.17. Bode plot for Example 1.3Example 1.4It is known that a voltage amplifier has a frequency response of a low−pass filter, a DC gain of80 dB , attenuation of – 20 dB per decade, <strong>and</strong> the 3 dB cutoff frequency occurs at 10 KHz.Determine the gain (in dB) at the frequencies 1 KHz, 10 KHz , 100KHz , 1 MHz, 10 MHz , <strong>and</strong>100 MHz .Solution:Using the given data we construct the asymptotic magnitude response shown in Figure 1.18 fromwhich we obtain the data shown on the table below.1−14<strong>Electronic</strong> <strong>Devices</strong> <strong>and</strong> <strong>Amplifier</strong> <strong>Circuits</strong> with MATLAB® / Simulink® / Sim<strong>Electronic</strong>s® Examples, Third EditionCopyright © Orchard Publicationss

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