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Electronic Devices and Amplifier Circuits

Electronic Devices and Amplifier Circuits - Orchard Publications

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Op Amp in the Inverting ModeNote 1: In the inverting mode, the resistor R connected between the non−inverting (+) input <strong>and</strong>ground serves only as a current limiting device, <strong>and</strong> thus it does not influence the opamp’s gain. So its presence or absence in an op amp circuit is immaterial.Note 2: The input voltage v in<strong>and</strong> the output voltage v outas indicated in the circuit of Figure 5.3,should not be interpreted as open circuits; these designations imply that an input voltageof any waveform may be applied at the input terminals <strong>and</strong> the corresponding output voltageappears at the output terminals.As shown in the relation of (5.1), the gain for this op amp configuration is the ratio – R f ⁄ R inwhereR fis the feedback resistor which allows portion of the output to be fed back to the input. Theminus (−) sign in the gain ratio – R f ⁄ R inimplies that the output signal has opposite polarity fromthat of the input signal; hence the name inverting amplifier. Therefore, when the input signal is positive(+) the output will be negative (−) <strong>and</strong> vice versa. For example, if the input is +1 volt DC <strong>and</strong> theop amp gain is 100, the output will be −100 volts DC. For AC (sinusoidal) signals, the output will be180° out−of−phase with the input. Thus, if the input is 1 volt AC <strong>and</strong> the op amp gain is 5, the outputwill be −5 volts AC or 5 volts AC with 180° out−of−phase with the input.Example 5.1Compute the voltage gain <strong>and</strong> then the output voltage for the inverting op amp circuitshown in Figure 5.4, given that = 1 mV. Plot v in<strong>and</strong> v outas mV versus time on the same setof axes.G vv inv out+v in−R in20 KΩR f−+120 KΩ+v out−Figure 5.4. Circuit for Example 5.1Solution:This is an inverting amplifier <strong>and</strong> thus the voltage gainG vis<strong>and</strong> sincethe output voltage isorG vR f= –------- = –R inG v = v out ⁄ v in120 KΩ-------------------- = – 620 KΩv out = G v v in = – 6×1v out = – 6 mV<strong>Electronic</strong> <strong>Devices</strong> <strong>and</strong> <strong>Amplifier</strong> <strong>Circuits</strong> with MATLAB® / Simulink® / Sim<strong>Electronic</strong>s® Examples, Third EditionCopyright © Orchard Publications5−3

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