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Water and Solute Permeability of Plant Cuticles: Measurement and ...

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56 3 Permeance, Diffusion <strong>and</strong> Partition Coefficients: Units <strong>and</strong> Their Conversion<br />

J v (cm 3 (STP) cm −2 s −1 )<br />

4e-7<br />

3e-7<br />

2e-7<br />

1e-7<br />

Vapour pressure <strong>of</strong> donor (cm Hg)<br />

0 0.48 0.95 1.43 1.90 2.375<br />

5e-7<br />

slope: 4.2 x 10 −7 cm 3 (STP)/cm 2 s<br />

0<br />

0.0 0.2 0.4 0.6 0.8 1.0<br />

Partial pressure <strong>of</strong> donor<br />

Fig. 3.2 Volume flux <strong>of</strong> water vapour across a polyethylene terephthalate (PET) membrane [Jv<br />

(STP) plotted vs partial pressure <strong>of</strong> donor (p/p0)]. Membrane thickness was 1 mm <strong>and</strong> temperature<br />

25 ◦ C. (Redrawn from Yasuda <strong>and</strong> Stannett 1962)<br />

other driving forces in more detail later. Since water activity <strong>of</strong> the vapour is equal<br />

to partial or fractional vapour pressure (p/p0), that is awv = p/p0, we can convert<br />

driving force in cmHg to partial pressure simply by dividing actual vapour pressure<br />

by saturation vapour pressure. With water at 25 ◦ C, saturation vapour pressure is<br />

2.375 cmHg.<br />

Based on the CGS system <strong>of</strong> the original literature, permeability (Pw) <strong>of</strong> a 1 cm<br />

thick membrane is<br />

Pw = Jw ×ℓ<br />

aw<br />

= 3.37 × 10−10 g(0.1cm)<br />

cm 2 s × 1<br />

4.0<br />

2.4<br />

3.2<br />

1.6<br />

0.8<br />

= 3.37 × 10 −11 gcm −1 s −1<br />

0<br />

J W X10 10 g cm −2 s −1<br />

(3.6)<br />

<strong>and</strong> since 1 g <strong>of</strong> water at 25 ◦ C has a volume <strong>of</strong> 1cm 3 , Pw is 3.37 × 10 −11 cm 2 s −1<br />

or 3.37 × 10 −15 m 2 s −1 . In this calculation the water flux enters as mass (g) <strong>and</strong> is<br />

converted to volume <strong>of</strong> liquid water. The driving force is water activity (or partial<br />

vapour pressure). With pure water as donor, Pw can be calculated by dividing<br />

(Jw ×ℓ) by the water concentration (Cw), which at 25 ◦ C is 1gcm −3 or 1,000kgm −3 .<br />

Cw depends much less on temperature than Cwv. For a solvent, a = γN where γ is<br />

the activity coefficient <strong>and</strong> N is the mol fraction. Considering water as pure ideal<br />

solvent, both γ <strong>and</strong> N are 1.0, <strong>and</strong> we have Cw = aw. Hence, Pw is numerically<br />

identical when driving forces are either Cw, awv or p/p0.<br />

In a closed system, equilibrium between vapour <strong>and</strong> liquid water is established.<br />

By definition pure water has an activity <strong>of</strong> 1.0, <strong>and</strong> water activity is numerically

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