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Gas Turbine Acoustics and Noise Control 149<br />

SPL = Lp =10Log P Pr<br />

2<br />

=20Log P<br />

Pr dB (10-1)<br />

where<br />

P = sound pressure measured in Pascals (N/m 2 ), and<br />

Pr = the reference pressure of 20 x 10 –6 Pa or 20μPa.<br />

In these equations the logarithm is to the base 10.<br />

Sound power is the rate at which acoustic energy is emitted.<br />

Sound power level (PWL) is described by:<br />

PWL = Lw =10Log W Wr dB (10-2)<br />

where<br />

W = calculated acoustic power in watts, and<br />

Wr = the reference power of 1 x 10 -12 watts.<br />

In general noise control applications we work strictly with the<br />

decibel levels but one must be aware that on occasion, listed sound<br />

power levels may use an old reference value of 1 x 10 -13 watts, and<br />

when converting to current standard, results in a ten-decibel reduction.<br />

Therefore, when specifying equipment sound power levels be<br />

sure to use the correct reference level, otherwise you can have a ten<br />

decibel deficiency in the design.<br />

Sound power can only be calculated from a set of sound pressure<br />

level measurements where a microphone measures the sound<br />

pressure over a given area that completely envelops the equipment<br />

being measured. For instance, a piece of equipment setting on the<br />

ground, measures 1m x 1m x 1m (5 square meters exposed surface<br />

area) but measuring the sound pressure level on a rectangular grid<br />

one meter away results in an area of 33 square meters. If the area<br />

averaged adjusted sound pressure level is 85 dB, then the sound<br />

power is:<br />

Lw = Lp + 10 LOG (Area) = 85 + 10 LOG(33) = 100 dB (10-3)<br />

This is a simplified demonstration but shows that when a supplier<br />

states his equipment does 85 dB at one meter that there is

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