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Op Amps for Everyone - The Repeater Builder's Technical ...

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Voltage Divider Rule<br />

source, through a component, or through a wire, because all currents are treated identically.<br />

Kirchoff’s current law is illustrated in Figure 2–4 and Equations 2–4 and 2–5.<br />

I 4 I 3<br />

I 1 I 2<br />

Figure 2–4. Kirchoff’s Current Law<br />

I (2–4)<br />

IN<br />

I OUT<br />

(2–5)<br />

I 1<br />

I 2<br />

I 3<br />

I 4<br />

2.3 Voltage Divider Rule<br />

When the output of a circuit is not loaded, the voltage divider rule can be used to calculate<br />

the circuit’s output voltage. Assume that the same current flows through all circuit elements<br />

(Figure 2–5). Equation 2–6 is written using Ohm’s law as V = I (R 1 + R 2 ). Equation<br />

2–7 is written as Ohm’s law across the output resistor.<br />

R 1<br />

V R 2<br />

I<br />

I<br />

V O<br />

Figure 2–5. Voltage Divider Rule<br />

I <br />

V<br />

(2–6)<br />

R 1<br />

R 2<br />

(2–7)<br />

V OUT<br />

IR 2<br />

Substituting Equation 2–6 into Equation 2–7, and using algebraic manipulation yields<br />

Equation 2–8.<br />

V OUT<br />

V<br />

R 2<br />

R 1<br />

R 2<br />

(2–8)<br />

A simple way to remember the voltage divider rule is that the output resistor is divided by<br />

the total circuit resistance. This fraction is multiplied by the input voltage to obtain the out-<br />

Review of Circuit <strong>The</strong>ory<br />

2-3

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