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Op Amps for Everyone - The Repeater Builder's Technical ...

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Amplifiers<br />

A.3.18 Inverting AC Amplifier<br />

V CC and resistors R set a dc level of V CC /2 at the inverting input. R G is connected to<br />

ground through a capacitor, thus the circuit functions as a buffer <strong>for</strong> dc. This causes the<br />

dc output voltage to be V CC /2, so the quiescent output voltage is the middle of the supply<br />

voltage, and it is ready to swing to either rail as the input signal commands.<br />

<strong>The</strong> ac gain is given in Equation A–25. R G and C <strong>for</strong>m a coupling network <strong>for</strong> the ac signal.<br />

Good coupling networks should be constant low impedance at the signal frequencies, so<br />

Equation A–26 should be satisfied to get good low-frequency per<strong>for</strong>mance. <strong>The</strong> lowest<br />

frequency component of the input signal, f MIN , is determined by completing a Fourier series<br />

on the input signal. <strong>The</strong>n, setting f MIN = 100f in Equation A–26 ensures that the 3-dB<br />

breakpoint introduced by R G and C is two decades lower than f MAX .<br />

R<br />

V OUT<br />

V F<br />

IN<br />

V CC<br />

R G<br />

2<br />

f <br />

1<br />

200R G<br />

C<br />

A–25<br />

A–26<br />

C<br />

R G<br />

V IN<br />

+V CC<br />

R<br />

R<br />

R F<br />

+V CC<br />

_<br />

+<br />

V OUT<br />

Output Amplitude — dB<br />

0<br />

–2<br />

–4<br />

–6<br />

–8<br />

–10<br />

–12<br />

–14<br />

–16<br />

–18<br />

V OUT<br />

Phase<br />

–20 170<br />

10 100 1 k 10 k 100 k<br />

f – Frequency – Hz<br />

V IN = 1 Vp-p<br />

C = 0.01 F<br />

V CC = 5 V R G = R F = R = 10 k<br />

<strong>Op</strong> Amp = TLV247x<br />

270<br />

260<br />

250<br />

240<br />

230<br />

220<br />

210<br />

200<br />

190<br />

180<br />

Phase — Degrees<br />

Figure A–22. Inverting AC Amplifier<br />

A-22

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