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fisica1-youn-e-freedman-exercicios-resolvidos

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5.109: a) For the same rotation rate, the magnitude of the radial acceleration is<br />

proportional to the radius, and for twins of the same mass, the needed force is<br />

proportional to the radius; Jackie is twice as far away from the center, and so must hold<br />

on with twice as much force as Jena, or 120 N.<br />

2<br />

b) ∑ F = mv r.<br />

Jackie<br />

v =<br />

(120 N) (3.6 m)<br />

30 kg<br />

= 3.8 m s.<br />

5.110: The passenger’s velocity is v = 2 π R t = 8.80 m s. The vertical component of the<br />

seat’s force must balance the passenger’s weight and the horizontal component must<br />

provide the centripetal force. Therefore:<br />

F sin θ = mg = 833 N<br />

seat<br />

2<br />

mv<br />

Fseat<br />

cos θ = = 188 N<br />

R<br />

Therefore tan θ = 833 N 188 N = 4.43; θ = 77. 3°<br />

above the horizontal. The magnitude of<br />

the net force exerted by the seat (note that this is not the net force on the passenger) is<br />

2<br />

2 ⎛ mv ⎞<br />

2<br />

2<br />

Fseat<br />

= ( mg)<br />

+<br />

⎜<br />

⎟ = (833 N) + (188 N)<br />

⎝ R ⎠<br />

= 854 N<br />

(b) The magnitude of the force is the same, but the horizontal component is reversed.<br />

5.111: a)<br />

2<br />

b) The upward friction force must be equal to the weight, so<br />

2 2<br />

µ n = m(4π<br />

R T ) ≥ mg and<br />

s<br />

µ s<br />

2<br />

2<br />

2<br />

gT (9.80 m s ) (1s 0.60 rev)<br />

µ<br />

s<br />

> =<br />

= 0.28.<br />

2<br />

2<br />

4π<br />

R 4π (2.5 m)<br />

c) No; both the weight and the required normal force are proportional to the rider’s<br />

mass.

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