fisica1-youn-e-freedman-exercicios-resolvidos

3.9: a) Solving Eq. (3.18) with y = 0 , v 0 and t = 0.350 s gives y = 0 600 m .
0 y
=
0
.
b) v x
t = 0.385 m c) v = v = 1.10 m s, v = −gt
= −3.43 m s, = 3.60 m s,72. 2°
below the horizontal.
x
0x
y
v
2 h
3.10: a) The time t is given by t = 7.82 s .
=
g
b) The bomb’s constant horizontal velocity will be that of the plane, so the bomb
travels a horizontal distance x = vx t = ( 60 m s)(7.82 s) = 470 m .
c) The bomb’s horizontal component of velocity is 60 m/s, and its vertical component
is − gt = −76.7 m s .
d)
e) Because the airplane and the bomb always have the same x-component of velocity and
position, the plane will be 300 m above the bomb at impact.