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fisica1-youn-e-freedman-exercicios-resolvidos

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7.80: (a) Stored energy = mgh = ( ρ V ) gh = ρ A(1<br />

m)<br />

gh<br />

3<br />

6<br />

= (1000 kg m )(3.0 × 10<br />

= 4.4 × 10<br />

12<br />

J.<br />

2<br />

m )(1 m)(9.8<br />

m<br />

2<br />

s<br />

)(150<br />

m)<br />

(b) 90% of the stored energy is converted to electrical energy, so<br />

(0.90) ( mgh)<br />

= 1000 kW h<br />

(0.90) ρ V gh = 1000 kW h<br />

3600 s<br />

(1000 kW h) (<br />

1 h<br />

)<br />

V =<br />

3<br />

(0.90)(1000 kg m ) (150 m) (9.8 m<br />

= 2.<br />

7 × 10<br />

3<br />

m<br />

3<br />

s<br />

2<br />

)<br />

Change in level of the lake:<br />

A∆h<br />

= V<br />

∆h<br />

=<br />

V<br />

A<br />

water<br />

.7 × 10<br />

=<br />

3.0 × 10<br />

3 3<br />

2 −4<br />

= 9.0 × 10<br />

6 2<br />

m<br />

m<br />

m<br />

7.81: The potential energy of a horizontal layer of thickness dy, area A, and height y is<br />

dU = ( dm)<br />

gy . Let ρ be the density of water.<br />

dm = ρ dV = ρA dy, so dU = ρAgy<br />

dy.<br />

The total potential energy U is<br />

h<br />

h<br />

1 2<br />

U = ∫ dU = ρAg∫<br />

ydy =<br />

2<br />

ρAh<br />

.<br />

0<br />

A = 3.0 × 10<br />

6<br />

m<br />

2<br />

0<br />

and h = 150 m, so U<br />

= 3.3×<br />

10<br />

14<br />

J = 9.2 × 10<br />

7<br />

kWh.<br />

7.82: a) Yes; rather than considering arbitrary paths, consider that<br />

r<br />

F<br />

⎡ ∂ ⎛ Cy<br />

= −⎢<br />

⎜ −<br />

⎣∂y<br />

⎝ 3<br />

3<br />

⎞⎤<br />

⎟⎥ ˆ. j<br />

⎠ ⎦<br />

b) No; consider the same path as in Example 7.13 (the field is not the same). For this<br />

force, F r = 0 along Leg 1, F<br />

r ⋅ d l<br />

r<br />

= 0 along legs 2 and 4, but F<br />

r ⋅ d l<br />

r<br />

≠ 0 along Leg 3.

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