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8.69: (This problem involves solving a quadratic. The method presented here formulates<br />

the answer in terms of the parameters, and avoids intermediate calculations, including<br />

that of the spring constant.)<br />

Let the mass of the frame be M and the mass putty be m. Denote the distance that the<br />

frame streteches the spring by x 0 , the height above the frame from which the putty is<br />

dropped as h , and the maximum distance the frame moves from its initial position (with<br />

the frame attached) as d.<br />

The collision between the putty and the frame is completely inelastic, and the<br />

m<br />

common speed after the collision is v<br />

0<br />

= 2gh<br />

.<br />

m+<br />

M<br />

After the collision, energy is<br />

conserved, so that<br />

1 2<br />

1<br />

2<br />

( m + M ) v ( ) (( )<br />

2<br />

0<br />

+ m + M gd = k d + x0<br />

− x0<br />

, or<br />

2<br />

2<br />

1 2<br />

m<br />

1 mg<br />

2<br />

(2gh)<br />

+ ( m + M ) gd = (( d + x )<br />

2<br />

0<br />

− x0<br />

,<br />

2 m + M<br />

2 x<br />

where the above expression for v 0<br />

, and k = mg x0<br />

have been used. In this form, it is seen<br />

that a factor of g cancels from all terms. After performing the algebra, the quadratic for d<br />

becomes<br />

d<br />

2<br />

⎛<br />

− d⎜2x<br />

⎝<br />

which has as its positive root<br />

0<br />

m ⎞<br />

⎟ − 2hx0<br />

M ⎠<br />

2<br />

m<br />

m + M<br />

= 0,<br />

⎡<br />

2<br />

2 ⎤<br />

⎢<br />

⎛ m ⎞ ⎛ m ⎞ h ⎛ m ⎞<br />

d = x0<br />

⎜ ⎟ + ⎜ ⎟ + 2<br />

⎥.<br />

⎢<br />

⎜<br />

0<br />

( )<br />

⎟<br />

⎥<br />

⎣<br />

⎝ M ⎠ ⎝ M ⎠ x ⎝ M m + M ⎠⎦<br />

For this situation, m = 4/3 M and h/x 0 = 6, so<br />

d = 0.232 m.<br />

0

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