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fisica1-youn-e-freedman-exercicios-resolvidos

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1 2 1 2<br />

7.24: From kx = mv , the relations between m, v, k and x are<br />

2<br />

2<br />

2 2<br />

kx = mv , kx = 5mg.<br />

2<br />

v<br />

Dividing the first by the second gives x = , and substituting this into the second gives<br />

2<br />

mg<br />

k = 25 , so a) & b),<br />

2<br />

v<br />

5g<br />

2<br />

(2.50 m s)<br />

x =<br />

= 0.128 m,<br />

2<br />

5(9.80 m s )<br />

(1160 kg)(9.80 m s )<br />

k = 25<br />

2<br />

(2.50 m s)<br />

2<br />

2<br />

= 4.46 × 10<br />

5<br />

N m.<br />

7.25: a) Gravity does negative work, − (0.75 kg)(9.80 m s )(16 m) = −118<br />

J. b)<br />

Gravity does 118 J of positive work. c) Zero d) Conservative; gravity does no net work<br />

on any complete round trip.<br />

2<br />

7.26: a) & b) − (0.050 kg)(9.80 m s )(5.0 m) = −2.5<br />

J.<br />

2<br />

c) Gravity is conservative, as the work done to go from one point to another is pathindependent.<br />

7.27: a) The displacement is in the y-direction, and since F r has no y-component, the<br />

work is zero.<br />

b)<br />

2<br />

P2<br />

x2<br />

2 12 N/m 3 3<br />

∫ F<br />

r<br />

⋅ dl<br />

r<br />

= −12∫<br />

x dx = − ( x2<br />

− x1<br />

) = −0.104 J.<br />

P1<br />

x1<br />

3<br />

3<br />

c) The negative of the answer to part (b), 0 .104 m d) The work is independent of<br />

path, and the force is conservative. The corresponding potential energy is<br />

U =<br />

(12 N<br />

2 3<br />

m ) x<br />

3<br />

3<br />

= (4 N m ) x .<br />

2

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