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fisica1-youn-e-freedman-exercicios-resolvidos

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1.15: a) If a meter stick can measure to the nearest millimeter, the error will be about<br />

0.13%.<br />

b) If the chemical balance can measure to the nearest milligram, the error will be<br />

−3<br />

about 8.3× 10 %. c) If a handheld stopwatch (as opposed to electric timing devices) can<br />

−2<br />

measure to the nearest tenth of a second, the error will be about 2.8×<br />

10 %.<br />

1.16: The area is 9.69 ± 0.07 cm 2 , where the extreme values in the piece’s length and<br />

width are used to find the uncertainty in the area. The fractional uncertainty in the<br />

2<br />

0 .07 cm<br />

area is 2 = 0.72%, and the fractional uncertainties in the length and width are<br />

9.69 cm<br />

0 .01cm<br />

0.01 cm<br />

5.10 cm<br />

= 0.20% and<br />

1.9 cm<br />

= 0.53%.<br />

1.17: a) The average volume is<br />

2<br />

( 8.50 cm) ( )<br />

3<br />

π 0.050 cm = 2.8 cm<br />

4<br />

(two significant figures) and the uncertainty in the volume, found from the extreme<br />

3<br />

values of the diameter and thickness, is about 0 .3 cm , and so the volume of a<br />

3<br />

cookie is 2.8 ± 0.3 cm . (This method does not use the usual form for progation of errors,<br />

which is not addressed in the text. The fractional uncertainty in the thickness is so much<br />

greater than the fractional uncertainty in the diameter that the fractional uncertainty in the<br />

volume is 10 % , reflected in the above answer.)<br />

8 .50<br />

b) = 170 ± 20.<br />

.05<br />

1.18: (Number of cars × miles/car . day)/mi/gal = gallons/day<br />

(2 × 10 8 cars × 10000 mi/yr/car × 1 yr/365 days)/(20 mi/gal) = 2.75 × 10 8 gal/day<br />

1.19: Ten thousand; if it were to contain ten million, each sheet would be on the order<br />

of a millionth of an inch thick.<br />

1.20: If it takes about four kernels to fill 1 cm 3 , a 2-L bottle will hold about 8000<br />

kernels.

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