fisica1-youn-e-freedman-exercicios-resolvidos

⎛ mi ⎞ ⎛ 1h ⎞ ⎛ 5280 ft ⎞ ft
1.10: a) ⎜60 ⎟
= 88
hr
⎜
3600s
⎟
⎜
1mi ⎟ ⎝ ⎠ ⎝ ⎠ ⎝ ⎠ s
⎛ ft ⎞ ⎛ 30.48cm ⎞ ⎛ 1m ⎞ m
b) ⎜32 = 9.8
2
⎟ ⎜ ⎟
2
s
⎜
1ft
⎟
⎝ ⎠ ⎝ ⎠ ⎝100 cm ⎠ s
⎛ g ⎞ ⎛100 cm ⎞ ⎛ 1kg ⎞ 3 kg
c) ⎜1.0 ⎟ = 10
3
⎟ ⎜ ⎟ ⎜
3
⎝ cm ⎠ ⎝ 1m ⎠ ⎝1000 g ⎠ m
3
1.11: The density is mass per unit volume, so the volume is mass divided by density.
3
3
V = 60 × 10 g 19.5g cm = 3077 cm
( ) ( )
3
4 3
Use the formula for the volume of a sphere, V = πr ,
3
1/ 3
to calculate r : r = ( 3V
4π
) = 9.0cm
7
7
7
1.12: (3.16×
10 s − π × 10 s) (3.16 × 10 s) × 100 = 0.58%
10 m
−3
1.13: a) = 1.1×
10 %.
3
890×
10 m
b) Since the distance was given as 890 km, the total distance should be 890,000
meters.
To report the total distance as 890,010 meters, the distance should be given as
890.01 km.
12 mm × 5.98 mm = 72 mm (two significant figures).
5 .98 mm
= 0.50 (also two significant figures).
1.14: a) ( ) ( )
2
b)
12 mm
c) 36 mm (to the nearest millimeter).
d) 6 mm.
e) 2.0.