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Basics of Fluid Mechanics, 2014a

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4.6. BUOYANCY AND STABILITY 117<br />

In going over these calculations, the calculations <strong>of</strong> the center <strong>of</strong> the area were not<br />

carried out. This omission saves considerable time. In fact, trying to find the center <strong>of</strong><br />

the area will double the work. This author find this method to be simpler for complicated<br />

geometries while the indirect method has advantage for very simple geometries.<br />

End Solution<br />

4.6 Buoyancy and Stability<br />

One <strong>of</strong> the oldest known scientific research<br />

on fluid mechanics relates to buoyancy<br />

due to question <strong>of</strong> money was car-<br />

a<br />

b<br />

Fig. -4.34. Schematic <strong>of</strong> Immersed Cylinder.<br />

ried by Archimedes. Archimedes principle<br />

is related to question <strong>of</strong> density and<br />

volume. While Archimedes did not know<br />

much about integrals, he was able to capture<br />

the essence. Here, because this material<br />

is presented in a different era, more advance mathematics will be used. While the<br />

question <strong>of</strong> the stability was not scientifically examined in the past, the floating vessels<br />

structure (more than 150 years ago) show some understanding 15 .<br />

The total forces the liquid exacts on a body are considered as a buoyancy issue.<br />

To understand this issue, consider a cubical and a cylindrical body that is immersed<br />

in liquid and center in a depth <strong>of</strong>, h 0 as shown in Figure 4.34. The force to hold the<br />

cylinder at the place must be made <strong>of</strong> integration <strong>of</strong> the pressure around the surface<br />

<strong>of</strong> the square and cylinder bodies. The forces on square geometry body are made only<br />

<strong>of</strong> vertical forces because the two sides cancel each other. However, on the vertical<br />

direction, the pressure on the two surfaces are different. On the upper surface the<br />

pressure is ρg(h 0 − a/2). On the lower surface the pressure is ρg(h 0 + a/2). The<br />

force due to the liquid pressure per unit depth (into the page) is<br />

F = ρg ((h 0 − a/2) − (h 0 + a/2)) lb= −ρgabl= −ρgV (4.147)<br />

In this case the l represents a depth (into the page). Rearranging equation (4.147) to<br />

be<br />

F<br />

= ρg (4.148)<br />

V<br />

The force on the immersed body is equal to the weight <strong>of</strong> the displaced liquid. This<br />

analysis can be generalized by noticing two things. All the horizontal forces are canceled.<br />

Any body that has a projected area that has two sides, those will cancel each other.<br />

Another way to look at this point is by approximation. For any two rectangle bodies,<br />

the horizontal forces are canceling each other. Thus even these bodies are in contact<br />

with each other, the imaginary pressure make it so that they cancel each other.<br />

15 This topic was the author’s high school name. It was taught by people like these, 150 years ago<br />

and more, ship builders who knew how to calculate GM but weren’t aware <strong>of</strong> scientific principles behind<br />

it. If the reader wonders why such a class is taught in a high school, perhaps the name can explain it:<br />

Sea Officers High School.<br />

r0<br />

h0

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