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Basics of Fluid Mechanics, 2014a

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11.4. ISENTROPIC FLOW 385<br />

Now, substituting c 2 = kRT or T = c 2 /k R equation (11.21) changes into<br />

1+ kRU2<br />

2 C p c 2 = T 0<br />

T<br />

(11.22)<br />

By utilizing the definition <strong>of</strong> k by equation (2.24) and inserting it into equation (11.22)<br />

yields<br />

1+ k − 1<br />

2<br />

U 2<br />

c 2 = T 0<br />

T<br />

(11.23)<br />

It very useful to convert equation (11.22) into a dimensionless form and denote<br />

Mach number as the ratio <strong>of</strong> velocity to speed <strong>of</strong> sound as<br />

Mach Number Definition<br />

M ≡ U c<br />

(11.24)<br />

Inserting the definition <strong>of</strong> Mach number (11.24) into equation (11.23) reads<br />

Isentropic Temperature relationship<br />

T 0<br />

T =1+k − 1<br />

2<br />

M 2<br />

(11.25)<br />

The usefulness <strong>of</strong> Mach number and<br />

equation (11.25) can be demonstrated by the<br />

following simple example. In this example a gas<br />

flows through a tube (see Figure 11.5) <strong>of</strong> any<br />

shape can be expressed as a function <strong>of</strong> only<br />

the stagnation temperature as opposed to the<br />

function <strong>of</strong> the temperatures and velocities.<br />

The definition <strong>of</strong> the stagnation state<br />

A<br />

T 0<br />

P 0<br />

ρ 0<br />

Q<br />

velocity<br />

Fig. -11.5. Perfect gas flows through a<br />

tube<br />

provides the advantage <strong>of</strong> compact writing. For example, writing the energy equation<br />

for the tube shown in Figure (11.5) can be reduced to<br />

B<br />

T 0<br />

P 0<br />

ρ 0<br />

˙Q = C p (T 0B − T 0A ) ṁ (11.26)<br />

The ratio <strong>of</strong> stagnation pressure to the static pressure can be expressed as the<br />

function <strong>of</strong> the temperature ratio because <strong>of</strong> the isentropic relationship as<br />

Isentropic Pressure Definition<br />

( ) k<br />

P 0<br />

P = T0<br />

k−1<br />

=<br />

(1+ k − 1 ) k<br />

M 2 k−1<br />

T<br />

2<br />

(11.27)

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