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Basics of Fluid Mechanics, 2014a

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7.1. THE FIRST LAW OF THERMODYNAMICS 201<br />

the liquid surface is straight 6 . Additionally, the temperature is assumed to constant.<br />

The control volume is chosen so that all the liquid is included up to exit <strong>of</strong> the pipe.<br />

The conservation <strong>of</strong> the mass is<br />

∫<br />

d<br />

dt<br />

∫V ✁ρdV + ✁ρU rn dA =0 (7.16)<br />

A<br />

which also can be written (because dρ<br />

dt =0)as<br />

∫<br />

∫<br />

U bn dA + U rn dA =0 (7.17)<br />

A<br />

Equation (7.17) provides the relationship between boundary velocity to the exit velocity<br />

as<br />

A<br />

AU b = A e U e (7.18)<br />

Note that the boundary velocity is not the averaged velocity but the actual velocity.<br />

The averaged velocity in z direction is same as the boundary velocity<br />

U b = U z = dh<br />

dt = A e<br />

A U e (7.19)<br />

The x component <strong>of</strong> the averaged velocity is a function <strong>of</strong> the geometry and was<br />

calculated in Example 5.12 to be larger than<br />

U x 2 r<br />

h<br />

A e<br />

A U e =⇒ U x<br />

∼<br />

2 r =<br />

h U b = 2 r dh<br />

h dt<br />

(7.20)<br />

In this analysis, for simplicity, this quantity will be used.<br />

The averaged velocity in the y direction is zero because the flow is symmetrical 7 .<br />

However, the change <strong>of</strong> the kinetic energy due to the change in the velocity field isn’t<br />

zero. The kinetic energy <strong>of</strong> the tank or container is based on the half part as shown in<br />

Figure 7.3. Similar estimate that was done for x direction can be done to every side <strong>of</strong><br />

the opening if they are not symmetrical. Since in this case the geometry is assumed to<br />

be symmetrical one side is sufficient as<br />

U y<br />

∼ =<br />

(π − 2)r<br />

8 h<br />

dh<br />

dt<br />

(7.21)<br />

6 This assumption is appropriated only under certain conditions which include the geometry <strong>of</strong> the<br />

tank or container and the liquid properties. A discussion about this issue will be presented in the<br />

Dimensional Chapter and is out <strong>of</strong> the scope <strong>of</strong> this chapter. Also note that the straight surface<br />

assumption is not the same surface tension effects zero.<br />

Also notice that the surface velocity is not zero. The surface has three velocity components which<br />

non have them vanish. However, in this discussion it is assumed that surface has only one component<br />

in z direction. Hence it requires that velocity pr<strong>of</strong>ile in xyto be parabolic. Second reason for this<br />

exercise the surface velocity has only one component is to avoid dealing with Bar-Meir’s instability.<br />

7 For the mass conservation analysis, the velocity is zero for symmetrical geometry and some other<br />

geometries. However, for the energy analysis the averaged velocity cannot be considered zero.

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