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Basics of Fluid Mechanics, 2014a

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380 CHAPTER 11. COMPRESSIBLE FLOW ONE DIMENSIONAL<br />

Solution<br />

The momentum equation written for the control volume shown in Figure (11.2) is<br />

R<br />

P F<br />

cs<br />

{ }} { { U (ρUdA)<br />

}} {<br />

(P + dP ) − P = (ρ + dρ)(c − dU) 2 − ρc 2 (11.8)<br />

Neglecting all the relative small terms results in<br />

(<br />

)<br />

dP =(ρ + dρ) c 2 ∼ 0 ∼ 0<br />

−✘✘✘✿<br />

2cdU +✘✘✘✘✘✿<br />

dU 2 − ρc 2 (11.9)<br />

And finally it becomes<br />

dP = c 2 dρ (11.10)<br />

This yields the same equation as (11.5).<br />

End Solution<br />

11.3.2 Speed <strong>of</strong> Sound in Ideal and Perfect Gases<br />

The speed <strong>of</strong> sound can be obtained easily for the equation <strong>of</strong> state for an ideal gas (also<br />

perfect gas as a sub set) because <strong>of</strong> a simple mathematical expression. The pressure<br />

for an ideal gas can be expressed as a simple function <strong>of</strong> density, ρ, and a function<br />

“molecular structure” or ratio <strong>of</strong> specific heats, k namely<br />

and hence<br />

c =<br />

P = constant × ρ k (11.11)<br />

P<br />

√<br />

{ }} {<br />

dP<br />

dρ = k × constant × constant × ρ k<br />

ρk−1 = k ×<br />

ρ<br />

= k × P ρ<br />

(11.12)<br />

Remember that P/ρ is defined for an ideal gas as RT , and equation (11.12) can be<br />

written as<br />

Ideal Gas Speed Sound<br />

c = √ kRT<br />

(11.13)<br />

Example 11.2:<br />

Calculate the speed <strong>of</strong> sound in water vapor at 20[bar] and 350 ◦ C, (a) utilizes the<br />

steam table (b) assuming ideal gas.

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