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Basics of Fluid Mechanics, 2014a

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10.3. POTENTIAL FLOW FUNCTIONS INVENTORY 355<br />

at<br />

End Caution: mathematical details<br />

lim<br />

r 0 →0<br />

✟2 r ✟✯ 0<br />

0 − 2 r cos θ<br />

r 2 + ✚r ✚❃0 2 0 − ✘ ✘✘✘ ✘✿ −<br />

✟2 r ✟✯ 0<br />

0 +2r cos θ<br />

2 rr 0<br />

0 cos θ r 2 + ✚r ✚❃0 2 0 + ✘ 2 rr ✘✘✘ ✘✿ 0<br />

0 cos θ<br />

= − cos θ<br />

4<br />

r<br />

(10.144)<br />

Combining the first and part with the second part results in<br />

φ = − Q 0 r 0<br />

π<br />

cos θ<br />

r<br />

(10.145)<br />

After the potential function was established the attention can be turned into the<br />

stream function. To establish the stream function, the continuity equation in cylindrical<br />

is used which is<br />

∇·U = 1 ( ∂rUr<br />

+ ∂U )<br />

θ<br />

r ∂r ∂θ<br />

The transformation <strong>of</strong> equations (10.46) and (10.48) to cylindrical coordinates results<br />

in<br />

U r = 1 r<br />

∂ψ<br />

∂θ<br />

(10.146a)<br />

U θ = − ∂ψ<br />

∂r<br />

(10.146b)<br />

The relationship for the potential function <strong>of</strong> the cylindrical coordinates was determined<br />

before an appear the relationship (10.66) and (10.67) in cylindrical coordinates to be<br />

U r = ∂φ<br />

∂r<br />

and<br />

(10.147a)<br />

The internal derivative is done by the quotient rule and using the prime notation as<br />

0 “ ”′ “ ”′ 1<br />

„<br />

ln f(ξ)<br />

«′<br />

= g(ξ) f(ξ) g(ξ) − g(ξ) f(ξ)<br />

B<br />

C<br />

@ “ ”<br />

g(ξ) f(ξ)<br />

2 A<br />

g(ξ)<br />

by canceling the various parts (notice the color coding). First canceling the square (the red color)<br />

and breaking to two fractions and in the first one canceling the numerator (green color) second one<br />

canceling the denominator (cyan color), one can obtain<br />

0<br />

„<br />

ln f(ξ)<br />

«′<br />

= ✟✟ g(ξ)<br />

✟ ✟ “ ”′<br />

f(ξ) g(ξ) −✟ ✟ “<br />

1<br />

”′ “ ”′ “ ”′<br />

g(ξ) f(ξ)<br />

g(ξ) f(ξ)<br />

g(ξ) ✟f(ξ)<br />

✟ B<br />

C<br />

@ “<br />

✟g(ξ)<br />

✟ ” A = −<br />

2 ✄ g(ξ) f(ξ)

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