06.09.2021 Views

Basics of Fluid Mechanics, 2014a

Basics of Fluid Mechanics, 2014a

Basics of Fluid Mechanics, 2014a

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

332 CHAPTER 10. POTENTIAL FLOW<br />

10.2 Potential Flow Function<br />

The two different Bernoulli equations suggest that some mathematical manipulations<br />

can provide several points <strong>of</strong> understating. These mathematical methods are known as<br />

potential flow. The potential flow is defined as the gradient <strong>of</strong> the scalar function (thus<br />

it is a vector) is the following<br />

U ≡ ∇φ (10.33)<br />

The potential function is three dimensional and time dependent in the most expanded<br />

case. The vorticity was supposed to be zero for the first Bernoulli equation. According<br />

to the definition <strong>of</strong> the vorticity it has to be<br />

Ω = ∇×U = ∇×∇φ (10.34)<br />

The above identity is shown to be zero for continuous function as<br />

∇φ<br />

{(<br />

}} {<br />

∇× i ∂φ<br />

)<br />

∂x + j∂φ ∂y + k∂φ ∂z<br />

( ∂ 2 φ<br />

= i<br />

+ j<br />

)<br />

∂y∂z − ∂2 φ<br />

∂z∂y<br />

( ∂ 2 φ<br />

∂z∂x − ∂2 φ<br />

∂x∂z<br />

) ( ∂ 2 )<br />

φ<br />

+ k<br />

∂y∂x − ∂2 φ<br />

∂x∂y<br />

(10.35)<br />

According to Clairaut’s theorem (or Schwarz’s theorem) 2 the mixed derivatives are<br />

identical ∂ xy = ∂ yx . Hence every potential flow is irrotational flow. On the reverse<br />

side, it can be shown that if the flow is irrotational then there is a potential function<br />

that satisfies the equation (10.33) which describes the flow. Thus, every irrotational<br />

flow is potential flow and conversely. In these two terms are interchangeably and no<br />

difference should be assumed.<br />

Substituting equation (10.33) into (10.24) results in<br />

(<br />

(∇φ) 2<br />

∂∇φ<br />

∂t<br />

+ ∇<br />

2<br />

∫ ( dP<br />

+ g l +<br />

ρ<br />

It can be noticed that the order derivation can be changed so<br />

∂∇φ<br />

∂t<br />

= ∇ ∂φ<br />

∂t<br />

) ) =0 (10.36)<br />

(10.37)<br />

Hence, equation (10.36) can be written as<br />

(<br />

∫ ( ) ) ∂φ<br />

∇<br />

∂t + (∇φ)2<br />

dP<br />

+ g l +<br />

=0 (10.38)<br />

2<br />

ρ<br />

2 Hazewinkel, Michiel, ed. (2001), ”Partial derivative”, Encyclopedia <strong>of</strong> Mathematics, Springer,<br />

ISBN 978-1-55608-010-4

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!