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Basics of Fluid Mechanics, 2014a

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434 CHAPTER 11. COMPRESSIBLE FLOW ONE DIMENSIONAL<br />

It should be noted that P should be replaced by P 0 in the calculations. The speed<br />

<strong>of</strong> sound at the entrance is<br />

c = √ kRT = √ 1.4 × 287 × 300 ∼ [ m<br />

]<br />

= 347.2<br />

sec<br />

and the density is<br />

ρ = P RT<br />

[ ]<br />

1, 000, 000 kg<br />

=<br />

287 × 300 =11.61 m 3<br />

The velocity at the entrance should be<br />

U = M ∗ c =0.08528 × 347.2 ∼ [ m<br />

]<br />

= 29.6<br />

sec<br />

The diameter should be<br />

√ √<br />

4ṁ<br />

D =<br />

πUρ = 4 × 0.2<br />

π × 29.6 × 11.61 ∼ = 0.027<br />

Nevertheless, for the sake <strong>of</strong> the exercise the other parameters will be calculated. This<br />

situation is reversed question. The flow rate is given with the diameter <strong>of</strong> the pipe. It<br />

should be noted that the flow isn’t choked.<br />

End Solution<br />

Example 11.17:<br />

A gas flows <strong>of</strong> from a station (a) with pressure <strong>of</strong> 20[bar] through a pipe with 0.4[m]<br />

diameter and 4000 [m] length to a different station (b). The pressure at the exit (station<br />

(b)) is 2[bar]. The gas and the sounding temperature can be assumed to be 300 K.<br />

Assume that the flow is isothermal, k=1.4, and the average friction f=0.01. Calculate<br />

the Mach number at the entrance to pipe and the flow rate.<br />

Solution<br />

First, the information whether the flow is choked needs to be found. Therefore, at first<br />

it will be assumed that the whole length is the maximum length.<br />

with 4 fL<br />

D<br />

4 fL<br />

D<br />

∣ =<br />

max<br />

4 × 0.01 × 4000<br />

0.4<br />

∣ = 400 the following can be written<br />

max<br />

= 400<br />

M<br />

4fL<br />

D<br />

T 0<br />

T 0<br />

∗T<br />

ρ<br />

ρ ∗T<br />

P<br />

P ∗T P 0<br />

P 0<br />

∗T<br />

0.0419 400.72021 0.87531 20.19235 20.19235 12.66915

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