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Basics of Fluid Mechanics, 2014a

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12.2. OBLIQUE SHOCK 515<br />

M x M yw θ w δ<br />

P y<br />

P x<br />

T y<br />

T x<br />

P 0y<br />

P 0x<br />

2.9290 2.2028 32.7822 15.0000 1.6695 1.5764 0.90041<br />

With the combined tables the ratios can be easily calculated. Note that hand calculations<br />

requires endless time looking up graphical representation <strong>of</strong> the solution. Utilizing<br />

the POTTO–GDC which provides a solution in just a few clicks.<br />

P 1<br />

P 3<br />

= P 1<br />

P 2<br />

P 2<br />

P 3<br />

=1.7985 × 1.6695 = 3.0026<br />

T 1<br />

T 3<br />

= T 1<br />

T 2<br />

T 2<br />

T 3<br />

=1.7344 × 1.5764 = 2.632<br />

End Solution<br />

Example 12.12:<br />

A similar example as before but here Mach angle is 29 ◦ and Mach number is 2.85.<br />

Again calculate the downstream ratios after the second shock and the deflection angle.<br />

Solution<br />

Here the Mach number and the Mach angle are given. With these pieces <strong>of</strong> information<br />

by utilizing the Potto-GDC the following is obtained:<br />

M x M ys M yw θ s θ w δ<br />

P 0y<br />

P 0x<br />

2.8500 0.48469 2.3575 0.0 29.00 10.51 0.96263<br />

and the additional information by utilizing the minimal info button in GDC provides<br />

M x M yw θ w δ<br />

P y<br />

P x<br />

T y<br />

T x<br />

P 0y<br />

P 0x<br />

2.8500 2.3575 29.0000 10.5131 1.4089 1.3582 0.96263<br />

With the deflection angle <strong>of</strong> δ =10.51 the so called reflective shock gives the following<br />

information<br />

M x M ys M yw θ s θ w δ<br />

P 0y<br />

P 0x<br />

2.3575 0.54894 1.9419 84.9398 34.0590 10.5100 0.97569<br />

and the additional information <strong>of</strong>

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