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Basics of Fluid Mechanics, 2014a

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11.6. ISOTHERMAL FLOW 435<br />

From the table M 1 ≈ 0.0419 ,and P 0<br />

P 0<br />

∗T ≈ 12.67<br />

∗T<br />

P 0<br />

∼<br />

28 =<br />

12.67 ≃ 2.21[bar]<br />

The pressure at point (b) by utilizing the isentropic relationship (M =1) pressure ratio<br />

is 0.52828.<br />

P 2 =<br />

P 0 ∗T<br />

(<br />

P2<br />

P 0<br />

∗T<br />

) =2.21 × 0.52828 = 1.17[bar]<br />

As the pressure at point (b) is smaller than the actual pressure P ∗

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