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Basics of Fluid Mechanics, 2014a

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484 CHAPTER 11. COMPRESSIBLE FLOW ONE DIMENSIONAL<br />

If only half <strong>of</strong> the fuel is supplied then the exit temperature is<br />

T 02 =<br />

Q 0.5 × 242.022<br />

+ T 01 = + 350/0.98232 ∼ 472.656[K]<br />

mC p 1.04<br />

The exit Mach number can be determined from the exit stagnation temperature as<br />

following:<br />

T 2<br />

T ∗ = T 01 T 02<br />

∗<br />

T 0 T 01<br />

The last temperature ratio can be calculated from the value <strong>of</strong> the temperatures<br />

T 2<br />

472.656<br />

=0.34686 ×<br />

T<br />

∗<br />

350/0.98232 ∼ 0.47685<br />

The Mach number can be obtained from a Rayleigh table or using Potto-GDC<br />

M<br />

T<br />

T ∗ T 0<br />

T 0<br />

∗<br />

P<br />

P ∗ P 0<br />

P 0<br />

∗<br />

ρ ∗ ρ<br />

0.33217 0.47685 0.40614 2.0789 1.1854 0.22938<br />

It should be noted that this example is only to demonstrate how to carry the<br />

calculations.<br />

End Solution

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